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3 years ago

12

2 m − 3 ≤ 5 m + 15 solve this equation

2 answers:

Paul [167]3 years ago

4 0

Answer:

<h3>m≥ -6</h3><h3 />

Step-by-step explanation:

Andru [333]3 years ago

4 0

Answer:

m ≥-6

Step-by-step explanation:

that is the procedure

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Ethan writes 2/3 of a page in 5/12 of a minute. How much time does it take him to write one page

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2/3 of a page in 5/12 of a minute

Multiply both fractions by 3/2

$\frac{2}{3} \times \frac{3}{2} = 1$

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So, Ethan can read 1 page in 5/8 of a minute.

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Prove that 1+cosA/sinA + sinA/1+cosA=2cosecA

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$\frac{1+cos\alpha}{sin\alpha}+\frac{sin\alpha}{1+cos\alpha}=2cosec\alpha\\\\L=\frac{(1+cos\alpha)(1+cos\alpha)+sin\alpha\cdot sin\alpha}{sin\alpha(1+cos\alpha)}=\frac{1+2cos\alpha+cos^2\alpha+sin^2\alpha}{sin\alpha(1+cos\alpha)}\\\\=\frac{1+2cos\alpha+1}{sin\alpha(1+cos\alpha)}=\frac{2+2cos\alpha}{sin\alpha(1+cos\alpha)}=\frac{2(1+cos\alpha)}{sin\alpha(1+cos\alpha)}\\\\=\frac{2}{sin\alpha}=2\cdot\frac{1}{sin\alpha}=2cosec\alpha=R$

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2 years ago

Which equation has a constant of proportionality equal to 1/2

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3 years ago

Find the twenty-fifth term of an arithmetic sequence if the first term is-1 and the common difference is 5. Write the first thre

denis-greek [22]

Answer:

1). $T_{25}=119$

2). $T_{1}=-23$

$T_{2}=-23+2=-21$

$T_{3}=-23+4=-19$

Step-by-step explanation:

First term of an arithmetic sequence is (-1) and common difference is 5.

Then we have to find twenty fifth term of this arithmetic sequence.

Since explicit formula of an arithmetic sequence is represented by

$T_{n}=a+(n-1)d$

Where $T_{n}$ represents nth term of the sequence.

a = first term

n = number of term

and d = common difference

Now we will find 25th term of this sequence.

$T_{25}=(-1)+(25-1)5$

= (-1) + 120

= 119

Similarly in second part of this question we have to find first three terms of an arithmetic sequence in which

$T_{21}=17$ and

$T_{50}=75$

Now from the explicit formula

17 = a + (21 - 1)d

17 = a + 20d --------(1)

75 = a + (50 - 1)d

75 = a + 49d --------(2)

Now we subtract equation 1 from 2

75 - 17 = 49d - 20d

29d = 58

d = $\frac{58}{29}=2$

By putting d = 2 in equation 1

17 = a + 20×2

17 = a + 40

a = 17 - 40

a = -23

Therefore, first three terms of this sequence will be

$T_{1}=-23$

$T_{2}=-23+2=-21$

$T_{3}=-23+4=-19$

8 0

3 years ago