Answer:
The answer in lowest terms is 15/17
Step-by-step explanation:
Hope that helps!
Answer:
(a)123 km/hr
(b)39 degrees
Step-by-step explanation:
Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.
Distance = Speed X Time
Therefore: PQ =50km/hr X 2 hr =100 km
It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.
Distance, QA=50km/hr X 2.5 hr =125 km
Using alternate angles in the diagram:
(a)First, we calculate the distance traveled, PA by plane Y.
Using Cosine rule
SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am
Time taken =1.5 hour
Therefore:
Average Speed of Y
(b)Flight Direction of Y
Using Law of Sines
The direction of flight Y to the nearest degree is 39 degrees.
This question is a little unclear. y= 4x - 3 is already in slope-intercept form. If you use (2,-3), then it would look like -3 = 4(2) - 3...
9514 1404 393
Answer:
- 90 student tickets
- 65 adult tickets
Step-by-step explanation:
For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...
6a +3(a+25) = 660
9a +75 = 660
9a = 585
a = 65
(a+25) = 90
The drama class sold 90 student tickets and 65 adult tickets.
The answers are:
5. 24v-80
6. 18x+12y-30
7. <span>b. c=12π, a=36π
8. a. 16</span><span>÷4
9. c. vertical angles</span>