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DerKrebs [107]
3 years ago
5

What is the next term of the geometric sequence? 189,63,21

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

7

Step-by-step explanation:

189-63=126

63-21=42

126/3=42

42/3=14

21-14=

7

Vinvika [58]3 years ago
7 0

Answer:

7

Step-by-step explanation:

Common ratio of 3 so 21/3 = 7

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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

JL = 2 * 13

JL = 26

Solving (c): KL

To solve for KL, we consider triangle KNL where:

\angle KNL = 90

and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

KL^2 = 394

KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

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miskamm [114]

Answer:

66.4°

Step-by-step explanation:

To find the angle XYZ, we are to use sine rule. For this, we have to first find ∠Z.

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90 + ∠Y + 23.6 = 180

113.6 + ∠Y = 180

∠Y = 180 - 113.6

∠Y = 66.4°

∠Y = ∠XYZ = 66.4°

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