Question

distance formula, d=(×2-×1)2+(y2-y1)2, what is the distance between point (8 4) and point (3,2) rounded to the nearest tenth ​

Answer 1

Answer:

5.4 units    

Step-by-step explanation:

1) Using the given distance formula of $d = \sqrt{(x_2-x_1)^2+(y_2-x_1)^2}$, find the distance between the pair of points. Substitute the x and y values of the points (8,4) and (3,2) into the formula and simplify:

$d = \sqrt{(8-3)^2+(4-2)^2}\\d = \sqrt{(5)^2+(2)^2} \\d = \sqrt{25+4} \\d = \sqrt{29}$

So, the distance is $\sqrt{29}$ units. Put that value into the calculator and round the result to the nearest tenth, or the first place to the right of the decimal point. The distance is 5.4 units.