Answer:
25p^12q^6πcm²
Step-by-step explanation:
Given the area of the circle expressed as;
A = πr^2
Given
r = 5p^6q^3 cm
Substitute into the formula
A = π(5p^6q^3 )²
A = π(25p^12q^6)
A = 25p^12q^6πcm²
hence the area of this circle in square centimeters is 25p^12q^6πcm²
Answer:
They are at the same height at 1.13 seconds.
Step-by-step explanation:
Remark
The rockets are at the same height when f(x) = g(x) [see below] are the same. So you can equate them.
Givens
f(x) = - 16x^2 + 74x + 9
g(x) = -16x^2 + 82x I have changed this so you don't have 2 f(x)s
Solution
- f(x) = g(x)
- -16x^2 + 74x + 9 = -16x^2 + 82x Add: 16x^2 to both sides
- -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x Combine terms
- 74x + 9 = 82x Subtract 74x from both sides
- 74x - 74x + 9 = 82x - 74x Combine
- 9 = 8x Divide by 8
- 9/8 = 8x/8
- x = 1 1/8 Convert to decimal
- x = 1.125
- x = 1.13 [rounded]
The slope of the first equation would be -5/2 because
2y=-5x+8
y=-5x/2+4
The y intercept of the 2nd equation is when x=0, so -7y=10
y=-10/7
The equation of the line would be y=-5x/2-10/7
Or in standard form....
5x/2+y=-10/7
5x+27=-20/7
Answer:
5-(1+5)= -1
-2(1+4)=-10
Step-by-step explanation:
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
