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shusha [124]
3 years ago
14

What is the domain and range of the relation? Is it a function or not?

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

domain is the x's and range is the y's and yes its a function bc if the x's and y's matched they wouldnt be but it is

Step-by-step explanation:

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An isosceles triangle has an angle that measures 26°. Which other angles could be in that
snow_tiger [21]

Answer:

26° 26° 128°

77° 77° 26°

Step-by-step explanation:

So we have two scenarios here.

One of them is if the base angles are 26°.

If that's true, the other angle is 128°

The other scenario is the opposite.

This means the base angles are 77°

5 0
3 years ago
How many months of the year have 28 days??
My name is Ann [436]
All 12 months have 28 days in it.
because every month has 28 days ( February) or more number of days like the other months(Jan, Mar..)
4 0
3 years ago
What is the solution of the following system?
erica [24]

Answer:

The answer to your question is: both lines are the same.

Step-by-step explanation:

                                   

                                             3x + 3y = 10

                                            -9x -9y = -30

Elimination method

                                            9x + 9x = 30

                                           -9x -  9y = -30

                                              0     0      0

8 0
3 years ago
Penelope earned $50 in May. She earned $60 in June.
laila [671]

Answer:

20% Increase

Step-by-step explanation:

Percentages can be put vice versa. So 20% Of 50 = 50% Of 20 Which Equals 10.

Mark me as brainliest please

3 0
3 years ago
Find f(b-2) if f(x) = x^2-6x+1
jasenka [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent expression is ~

  • f(b - 2) =  {b}^{2}  - 10b + 17

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's evaluate f(b - 2) ~

  • f(x) =  {x}^{2}  - 6x + 1

  • f(b - 2) = (b - 2) {}^{2}  -6 (b - 2) + 1

  • \mathcal{ {f(b - 2) =  {b}^{2}   +  2 {}^{2}  - (2 \times b \times 2) - 6b + 12}}

  • f(b - 2) =  {b}^{2}   + 4 - 4b - 6b + 12 + 1

  • f(b - 2) =  {b}^{2}  - 10b + 17
4 0
3 years ago
Read 2 more answers
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