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kirill115 [55]
3 years ago
14

$947.50 - $189.50 = ?Am I not smart or what?

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0
<span>   $947.50
</span> - $189.50
_________
$758.00

So, to do this first we start at the far right and go to the left.

   $947.50 - $189.50_________
   $      .00
0-0= 0
5-5= 0

You then bring down the decimal.

   $947.50 - $189.50_________
    $   8 .00
Because you cannot subtract 9 from 7, you borrow one from the number to the left of it and 7 turns into a 17 as 4 turns into a 3. So then, 17-9=8.
         17
   $93-7-.50         -7- = This means the 7 has been canceled out and turned  - $189.50                        into the 17 above _________         8 .00
This happens again with subtracting 3 from 8 in which you take one from the number beside which happens to be 9 and make it 8.

          17
   $8-3--7-.50         -7- and -3- = This means the 7 has been canceled out                                                         and turned into the 17 above 
  - $189.50                        _________    $ 58 .00
So then, 13-8=5. Finally 8-1= 7

   $947.50
 - $189.50
_________
$758.00

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Which expression is equivalent to m^2-13m-30?
sergiy2304 [10]

Answer: First option

Step-by-step explanation:

You have the quadratic equation given in the problem:

m^2-13m-30

To find an equivalent expression you cacn factorize. Find two numbers whose sum is -13 and whose product is -30.

These numbers would be -15 and 2.

Therfore, you obtain the following equivalent expression:

(m-15)(m+2)

If you don't want to apply the method above, you can use the quadratic formula:

x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

Where:

a=1\\b=-13\\c=-30

When you susbstitute values you obtain that:

x=15\\x=-2

Then you can rewrite the equation as (m-15)(m+2)

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2 years ago
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14 is the length of the missing side.

Step-by-step explanation:

Use pythagorean theorem.

48^{2}+b^{2}=50^{2}

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Traveling math word problem - thank you! :)
Anni [7]

<u>We are given:</u>

car and train leave at the same time

average velocity of car = 50 miles/hour

average velocity of train = 70 miles/hour

train arrives 2 hours early

<u>Assuming variables and making equations!</u>

let the time taken by the train = t hours

since the car arrived late, it took more time as compared to the train

time taken by the car = t + 2 hours

since the distance from Pasadena to Sacramento doesn't change, both the vehicles covered the same distance, d

<u>Distance travelled by the car:</u>

d = 50 \frac{miles}{hour} * (t+2) hours                             [distance = velocity * time]

d = 50(t+2) miles

rewriting in terms of t

t = \frac{d-100}{50}

<u>Distance travelled by the train:</u>

d = 70 \frac{miles}{hour} * t hours

d = 70t miles

rewriting in terms of t

t = \frac{d}{70}

now we have two expressions for t, both of which are equal because t is just the time taken by the train

<u>Finding the distance:</u>

<u></u>t = \frac{d-100}{50}<u></u>

<u></u>t = \frac{d}{70}<u></u>

because t is the same:

\frac{d-100}{50} = \frac{d}{70}

\frac{d-100}{5} = \frac{d}{7}

7(d - 100) = 5(d)

7d - 700 = 5d

(7d - 5d) - 700 = 0                                        [subtracting 5d from both sides]

2d = 700                                                       [adding 700 on both sides]

d = 350 miles                                               [dividing both sides by 2]      

The distance between Pasadena and Sacramento is 350 miles!

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