Since there are no figures given, I will give an example.
You are given a silo that is shaped as
a closed cylinder with a conical end. The diameter of the silo is 4 ft, the
length of the cylindrical part is 6 ft, and the entire length of the silo is
10.5 ft. Suppose that you are asked to find the total volume of
grains that can be stored in the silo.
Given:
Cylinder part
D = 4 ft
H = 6 ft
Cone part
H = 10.5 – 6 = 4.5ft
D = 4ft
Required:
Volume of silo
Solution:
V of cylinder = πr²H
V of cylinder = π(4/2)²(6)
V of cylinder = 75.4 ft³
V of cone = πr²H/3
V of cone = π(4/2)²(4.5/3)
V of cone = 18.85 ft³
Total volume = 94.25 ft³
Answer:
your answer should be b= 17
Answer:
AB is perpendicular to [GH] and GH is [A]
Step-by-step explanation:
<span>Answer 61 73-66= 7 21-13 = 8 ?? -52= 9 20-10 = 10 ??=61</span>
Answer:
72º
Step-by-step explanation:
Angles at a point = 360º
Number of wedges = 5
Angle of each wedge
= 360 ÷ 5
= 72º
