3 years ago

What are the solutions to the following equation?

Mathematics

2 answers:

Aneli [31]3 years ago

7 0

Answer -8.5

Step-by-step explanation:

gregori [183]3 years ago

3 0

Answer: -8.5

Step-by-step explanation:

I got it right on edg

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X²- 12x + a = (x-b)² Find the Value of a and value of b

maxonik [38]

Answer:

a = 36 , b = 6

Step-by-step explanation:

expand the right side using FOIL and compare coefficients with like terms on left side.

(x - b)²

= x² - 2bx + b² , compare to x² - 12x + a , then

- 2b = - 12 ( divide both sides by - 2 )

b = 6

and a = b² = 6² = 36

5 0

2 years ago

Passing through 1,-4 and -2,5

Nataly_w [17]

Answer:

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2 years ago

Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.

Andreyy89

Let ${s_n}_{n\in\Bbb N}$ be a sequence that converges to $L$ . This means for any $\varepsilon>0$ , there is some $N$ such that $|s_n-L|$ for all $n>N$ . From this inequality we see that $|(s_n-L)-0|$ , so it follows that $s_n-L\to0$ .

On the other hand, let ${s_n-L}$ be a sequence that converges to 0. This means $|(s_n-L)-0|$ for all large enough $n$ , and we get the simpler inequality for free, $|s_n-L|$ , so it follows that $s_n\to L$ .