ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
y=1/2x
Step-by-step explanation:
Look at the graph, all you need is the first point.
Y is at 4 and X is at 2. We can divide y/x to get 4/2=1/2x
the answer is D :) i hope you have a good day
Answer:
1 draw a line of 7.5 cm YZ by scale
2 construct the 90 degree with the help of protecter
3 then cut arc of 6 cm on 90 degree of angle & mark as X
4 join X and Z by scale
