What are the solutions to the following equation?

Does anyone know this answer? timed test

omeli [17]

The answer is
(2/1/8)

D

3 0

3 years ago

Read 2 more answers

Can someone please solve this before I get my phone taken away?

prisoha [69]

Answer:

option 1 or should be

Step-by-step explanation:

4/1.5 is 2.6 and 2/3 as a fraction is 66666 so yeah

6 0

3 years ago

1. A boat drifted 15 m out into the water off Ocean Beach, where the shore drops off

Lunna [17]

The correct responses found using trigonometric ratios are as follows;

Brooke's cannot bring the boat back without getting water over her boots.
The plan will not be approved
The plane will not disturb
The company can not use the chimney legally
The Long company will build the bridge
The fireman can reach her.
The lift does not take the skiers up to the bar.
Eric will be able to see his Dad's plane.
The 73 m. brace

<h3>How can trigonometric ratios be used to find the right responses?</h3>

1. The depth of the water = 15 × tan(4°) = 1.049 m

The height of Brooke's boot = 1 m

Therefore;

Brooke's cannot bring the boat back without getting water over her boots.

2. The angle of elevation of the plan = arccos(99/100) ≈ 8.110°

Given that the angle of elevation the plan, 8.110°, is more than 8° limit, we find;

The plan will not be approved.

3. Height reached by the plane = 9 × tan(21°) = 3.455

Therefore;

The plane will not disturb.

4. Height of the chimney at the factory = 50 × tan(51°) = 61.745

The minimum chimney height = 65 m.

Therefore;

The company can not use the chimney legally.

6. Length of the bridge = 72 × tan(55°) ≈ 102.83

Therefore;

The Long company will build the bridge because it is longer than 100 m. but not more than 103 m.

7. Height reached by the ladder = 26 × sin(43°) ≈ 17.7

Therefore;

The fireman can reach her.

8. Height reached by the ski lift = 1000 × sin(29°) ≈ 484.8

Therefore;

The lift does not take the skiers up to the bar.

9. Height reached by plane = 26 × tan(9°) ≈ 4.12

The plane flies under the cloud therefore;

Eric will be able to see his Dad's plane.

10. Length required for the metal brace = 21/(cos(73°)) ≈ 71.83

Therefore;

The brace that wastes less metal is the 73 m. brace, because the 71 m. brace is not long enough and two braces will be required.

Learn more about trigonometric ratios here:

brainly.com/question/24349828

#SPJ1

7 0

1 year ago

Need help ASAP !!!!!

Flura [38]

Answer:

10

Step-by-step explanation:

12x + 20+40 = 180

12x = 120

X = 10

6 0

3 years ago

Jennifer hit a golf ball from the ground and it followed the projectile ℎ(t)= −15t^2+100t, where t is the time in seconds, and ℎ

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

In order to find the max height the ball reached, we have to complete the square on that quadratic. That will also, conveniently so, give us the number of seconds it will take the ball to reach that max height, that answer to part b. Let's begin to complete the square. Normally, you would move the constant over to the other side of the equals sign, but there is no constant here. The next step is to get the leading coefficient to be a 1, and ours right now is a -15. So we have to factor it out. Here's where we start the process of completing the square.

$-15(t^2-\frac{20}{3}t)=0$ Next step is to take half the linear term, square it, and add it to both sides. Our linear term is 20/3. Half of 20/3 is 20/6, and 20/6 squared is 400/36.

$-15(t^2-\frac{20}{3}t+\frac{400}{36})=0+???$ Because this is an equation, what we add to the left side also has to be added to the right. BUT we didn't just add in 400/36, because we have that -15 out front as a multiplier that refuses to be ignored. What we actually added in was -15(400/36):

$-15(t^2-\frac{20}{3}t+\frac{400}{36})=0-\frac{500}{3}$

The reason we do this is to create a perfect square binomial on the left which will serve as the number of seconds, h, in the vertex (h, k), where h is the number of seconds it takes the ball to reach its max height, k. Simplifying both sides then gives us:

$-15(t-\frac{20}{6})^2=-\frac{500}{3}$ Finally, we will move the right side over by the left and set the quadratic back equal to h(t):

$h(t)=-15(t^2-\frac{20}{3})^2+\frac{500}{3}$ and from that you can determine that the vertex is $(\frac{20}{3},\frac{500}{3})$ .

The answer to a. is vound in the second number of our vertex: k, the max height. The max of the golf ball was 500/3 feet or 166 2/3 feet.

Part b is found in the first number of the vertex: h, the number of seconds it took the golf ball to reach that max height. The time it took was 3 1/3 seconds.

Part c. is to state the domain (the time) and the range (the height) of the ball.

Domain is

D: {x | 0 ≤ x ≤ 3 1/3} and

Range is

R: {y | 0 ≤ y ≤ 166 2/3}

8 0

3 years ago