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3 years ago

Need help ASAP !!!!!

Mathematics

1 answer:

Flura [38]3 years ago

6 0

Answer:

Step-by-step explanation:

12x + 20+40 = 180

12x = 120

X = 10

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I don't know what the answer is and I need help

gladu [14]

Answer:

To solve this, you want to express the change to x directly since you are moving along the horizontal or X-axis. Thus, to show a 4 unit translation to the left, we would do g(x) = (x + 4) - 5 = x - 1.

4 0

3 years ago

The value of Peter's house has risen 30% a year for the last 3 years. If the value of Peter's home 3 years ago was $120,000.00,

navik [9.2K]

Step-by-step explanation:

The price has gone up by 30% each year so each year it is 130% compared to last year. that means a price rate of 1.3^n, with n as number of years gone by. In this case n=3 so 1.3^3=2.197. $120,000.00×2.197=$263,640.00, which is D

4 0

4 years ago

A company makes a profit of $y (in thousand dollars) when it produces x computers,

leva [86]

Using quadratic function concepts, it is found that:

a) The value of a is -2000.

b) The maximum profit the company can make is of $5,000,000, when 150 computers should be produced.

c) Between 140 and 160 computers need to be produced.

The profit is modeled by:

$y = a(x - 100)(x - 200)$

Item a:

If 120 computers are produced, the profit will be $3,200,000, hence when $x = 120, y = 3200000$ , and this is used to find a.

$y = a(x - 100)(x - 200)$

$3200000 = a(120 - 100)(120 - 200)$

$-1600a = 3200000$

$a = -\frac{3200000}{1600}$

$a = -2000$

The value of a is -2000.

Item b:

We first place the quadratic function into standard form, thus:

$y = -2000(x - 100)(x - 200)$

$y = -2000(x^2 - 300x + 20000)$

$y = -2000x^2 + 600000x - 40000000$

Which has coefficients $a = -2000, b = 600000, c = -40000000$ .

Then, we have to find the vertex:

$x_V = -\frac{b}{2a} = -\frac{600000}{2(-2000)} = 150$

$\Delta = b^2 - 4ac = (600000)^2 - 4(-2000)(-40000000) = 40000000000
$

$y_V = -\frac{\Delta}{4a} = -\frac{40000000000
}{4(-2000)} = 5000000$

The maximum profit the company can make is of $5,000,000, when 150 computers should be produced.

Item c:

We are working with a concave down parabola, hence the range is between the roots of:

$y = -200x^2 + 600000x - 40000000$

$4800000 = -200x^2 + 600000x - 40000000$

$-200x^2 + 600000x - 44800000 = 0$

The coefficients are $a = -200, b = 600000, c = -44800000$ .

Then:

$\Delta = b^2 - 4ac = (600000)^2 - 4(-2000)(-44800000) = 1600000000$

$x_1 = \frac{-b - \sqrt{Delta}}{2a} = \frac{-600000 - \sqrt{1600000000}}{2(-2000)} = 160$

$x_2 = \frac{-b + \sqrt{Delta}}{2a} = \frac{-600000 + \sqrt{1600000000}}{2(-2000)} = 140$

Between 140 and 160 computers need to be produced.

A similar problem is given at brainly.com/question/24705734

8 0

3 years ago

A=c+(-10) Solve for c in terms of other variables.

True [87]

To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)

so
A+ 10 = c -10 + 10
we get
A+ 10 = c

lets say it wasn't -10 but positive 10.

A = c + 10 then we would subtract 10 from both sides

A -10 = c + 10 - 10
we get
A - 10 = C

5 0

4 years ago

How to solve 5/6y + 1 = -1/2y + 1/4

True [87]

Answer:

y= -1/4

y= -0.25

Step-by-step explanation:

5/6y+1= -1/2y+1/4

Subtract 1 from both sides

5/6y= -1/2y-3/4

Add 1/2y to both sides

1 1/3y= -3/4

Divide both sides by 1/3

y= -1/4

y= -0.25

6 0

3 years ago