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Nitella [24]
3 years ago
8

The length of a rectangle is twice its width the perimiter is 60 ft find its area

Mathematics
1 answer:
Masja [62]3 years ago
4 0

Hello,

let's assume a=the length and b the width.

\left\{\begin{array}{ccc}a&=&2*b\\2(a+b)&=&60\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\a+b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}a&=&2*b\\3b&=&30\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}b&=&10\\a&=&20\\\end{array}\right.\\\\\\Area=10*20=200\ (ft^2)\\

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