Answer:
See picture
Step-by-step explanation:
Answer:
1) E
2) D
3) G
4) I
Step-by-step explanation:
1)
P = 2(l + w)
P = 2(3a + 3 + 8a - 12)
P = 2(11a - 9)
P = 22a - 18
2)
P = 22a - 18
P = 22(3) - 18
P = 66 - 18
P = 48
3)
P = a + b + c
P = 3b + 7 + 7b - 2 + 7b - 2
P = 17b + 3
4)
P = 17b + 3
P = 17(6) + 3
P = 102 + 3
P = 105
Answer:
50 deg
Step-by-step explanation:
The circles are congruent, so all radii of both circles are congruent.
The given central angles are congruent, so the triangles are congruent by SAS.
Since each triangle has 2 congruent sides (the radii), opposite angles are congruent.
m<DFE = m<J = 80 deg
m<H = m<G = x
m<H + m<G + m<J = 180
x + x + 80 = 180
2x + 80 = 180
2x = 100
x = 50
m<H = 50
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
Answer:
1st one: -3,-4 away
2nd one: Lets just say I got kinda confused on that one so sorry for any inconvenience on my behalf from this question.
Step-by-step explanation:
I will call (-3,-4) Point A and I'll call (0,0) Point B. Point A is at (-3,-4) and Point B is obviously at the origin. That makes it easy, because you just subtract Point A by Point B to find how far away they are.
