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lapo4ka [179]
3 years ago
8

If two polygons are similar, they are congruent. Always true sometimes true or never true?

Mathematics
1 answer:
charle [14.2K]3 years ago
5 0

Answer:

It is true.

Step-by-step explanation:

congruent polygons have the exact same size and are a perfect match because all corresponding parts are congruent (equal). ... This means that if two polygons are similar, then their corresponding angles are congruent

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Step 2 , supposed to be 4^-15 instead of 4^-2. Always multiply the exponents together.

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NEED HELP ASAP!!!!!!! WILL MARK CORRECT ANSWER BRAINLIEST!!!!
Ganezh [65]

Answer:

(x + 1)² + (y - 1)² = 1.5625

Step-by-step explanation:

From the picture we see:

The radius is 5 units. Each unit is .25 so the radius is 1.25.

The centre or middle M= ( -1, 1 )

Circle with centre M and radius r :

(x - xM)² + (y - yM)² = r²

xM = -1

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(x - (-1))² + (y - 1)² = (1.25)²

(x + 1)² + (y - 1)² = 1.5625

6 0
3 years ago
Rewrite without paraentheses and simply <br> (Y-2)^2
german

show how to simply that

(y-2)^2

(y-2)(y-2)

Y^2-2y-2y+4

y^2-4y+4

the answer was y^2-4y+4

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6 0
3 years ago
What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6?
Artyom0805 [142]

Answer:

y=\frac{1}{6} (x-4)-\frac{9}{2}

Step-by-step explanation:

∵ The quadratic equation form is :

y = [1/2(b - k)] (x - a)² + (b + k)/2

Where (a , b) is the focus and directrix y = k

∵ The focus is (4 , -3) and directix is y = -6

∵ y=\frac{1}{2(-3-(-6))} (x-4)^{2}+\frac{(-3)+(-6)}{2}

∴ y=\frac{1}{6} (x - 4)^{2}+\frac{-9}{2}

∴ y=\frac{1}{6} (x-4)-\frac{9}{2}

another way:

Assume that (x , y) is the general point on the parabola

∵ The distance between the directrix and (x , y) = the distance between the focus and (x , y)

By using the distance rule:

∵ (y - -6)² = (x - 4)² + (y - -3)² ⇒ (y + 6)² = (x - 4)² + (y + 3)

∴ y² + 12y + 36 = (x - 4)² + y² + 6y + 9

∴ 12y - 6y = (x - 4)² + 9 - 36

∴ 6y = (x - 4)² - 27 ⇒ ÷ 6

∴ y = 1/6 (x - 4)² - 9/2

4 0
3 years ago
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