The volume of the drum after chilled quickly is 3.6 L.
<u>Explanation:</u>
As per the Charles Law, for any gas at constant pressure, volume of the gas is in direct proportion with the temperature measured in Kelvin. As the temperature increases, the gas expands and vice versa.
After chilling the drum, the volume will get reduced and it can be found as,
V2 = 
= 
= 3.6 L
Here the drum is chilled quickly, that is temperature is reduced and so the volume also decreases.
The industrial synthesis of ammonia is spontaneous.
to to prove this one calculate the gibbs free energy(delta G)
= delta G = Delta H -T delta s
delta H = -92.2 kj in joules -92.2 x1000 =-92200j
delta s = -199j/k
T= 25+273= 298k
delta G is therefore= -92200-298(-199)=-32898j
since delta G is negative the reaction is therefore spontaneous
At STP, it is at 273 K and 1.00 atm.
Use PV=nRT to and solve for n (number of mol of N2)
1.00 atm • 4.40L / 0.08206 Latm/molK • 273 K = 0.196 mol N2
There are two mol of N2 for every two mol of NH4NO2 (the number of mol of both are equal)
Find the molar mass of NH4NO2 = 64.1 g
Multiply the number of mol by the molar mass
0.196 mol • 64.1 = 12.6 g NH4NO2
Reaction between mercury (ii) sulfide with Calcium oxide is as shown;
4 HgS +4 CaO = 4 Hg + 3 CaS + CaSO4
The molar mass of HgS is 232.66 g/mol
The number of moles = 31.28/232.66
= 0.1344 moles
The mole ratio of HgS : CaO is 1: 1
Therefore, the number of moles of Calcium oxide is 0.1344 moles
1 mole of CaO Contains 56 g/mol
Thus, the mass of CaO is 56 g/mol
= 0.1344 moles × 56 g/mol
= 7.5264 g
Matter is anything that has mass and takes up space.
Hope this helps!! (:
