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m_a_m_a [10]
3 years ago
15

Matter doesn’t have to take up space as long as it has mass TRUE or FALSE

Chemistry
2 answers:
statuscvo [17]3 years ago
8 0
False anything that has mass takes up the space
DIA [1.3K]3 years ago
3 0
The answer is false
 its actually almost the exact opposite                                 
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Two isotopes of the same element must have the same
emmainna [20.7K]

Answer:

atomic number

Explanation:

isotope is a family of an element with the same atomic number but different mass number.

3 0
2 years ago
What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
Alika [10]

Answer:- B: 1.10g H_2 is the right answer.

Solution:- The balanced equation is:

O_2(g)+2H_2(g)\rightarrow 2H_2O(g)

We have been given with 8.75 grams of oxygen and asked to calculate the grams of hydrogen needed to react with given grams of oxygen according to the balanced equation.

From balanced equation, 1 mole of oxygen reacts with 2 moles of hydrogen.

So, let's convert grams of oxygen to moles and multiply it by the mole ratio to calculate the moles of hydrogen that are easily converted to grams on multiplying by it's molar mass.

The complete set up looks as:

8.75g O_2(\frac{1mole}{32g})(\frac{2mole H_2}{1mole O_2})(\frac{2.02g}{1mole})

= 1.10g H_2

Hence, the right option is B: 1.10g H_2 .



7 0
3 years ago
Read 2 more answers
Answer choices are A. Constant speed<br> B. Stopped<br> C.Moving sideways<br> D.Accelerating
Maurinko [17]
B.stopped
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7 0
2 years ago
What is a sign that a person may be abusing drugs?
lidiya [134]

Answer:

answer is a because drugs do so to the person.

6 0
3 years ago
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Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st
Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have  reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.

Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0
3 years ago
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