Answer:
The speed of plane against wind S 1 = 1020 kmph And
The speed of plane with wind S 2 = 1260 kmph
Step-by-step explanation:
Given as :
The distance of airplane against the wind = D 1 = 3060 km
The time taken in against the wind = T 1 = 3 hours
The distance of airplane with the wind = D 2 = 7560 km
The time taken in with the wind = T 2 = 6 hours
Now, Speed of plane against the wind = 
So, S 1 = 
Or, S 1 =
= 1020 kmph
Similarly
Speed of plane with the wind = 
Or, S 2 = 
Or, S 2 =
= 1260 kmph
Hence The speed of plane against wind S 1 = 1020 kmph And
The speed of plane with wind S 2 = 1260 kmph Answer
Answer:
(X+5)^2 + (Y-2)^2 =49
Step-by-step explanation:
Equation of the circle
(X-a)^2+(Y-b)^2= r^2
Center=(-5 ; 2) , so : a= -5 y b=2
y r=7
Answer: b ≤ -18
<u>Step-by-step explanation:</u>
Isolate the variable by multiplying both sides by -3. Remember that when you multiply or divide by a negativem the symbol flips.

9514 1404 393
Answer:
ML = 7.5
Step-by-step explanation:
The parallel lines divide the transversals proportionally.
ML/LK = JH/HG
ML/10 = 6/8
ML = 10(6/8) = 7.5
The length of ML is 7.5.
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We don't need to solve for x. If ML = x-2, then x=9.5.