Ask question

Ask question

All categories

Ksenya-84 [330]

3 years ago

12

How much more area does a large pizza with a 12 in. diameter have than a small pizza with an 8 in. diameter? Round your answer t

o the nearest square inch.

1 answer:

ivolga24 [154]3 years ago

4 0

Answer: About 63 in²

Step-by-step explanation:

<u>Area of circle = π · r²</u>

r = radius length
π ≈ 3.14

<u>Area of large pizza:</u>

$\pi *r^{2} =3.14*6^{2} =3.14*36=113.04$

<u>Area of small pizza:</u>

$\pi *r^{2} =3.14*4^{2} =3.14*16=50.24$

<u>Difference in area:</u>

$113.04-50.24=62.8$

You might be interested in

Please help with this question! It’s Algebra Math 2

juin [17]

Zero of 7 with a multiplicity of 3 means one factor is $(x-7)^3$

Zero of -1 with a multiplicity of 2 means one factor is $(x+1)^2$

Zero of 5 with a multiplicity of 1 means one factor is $(x-5)$

Multiplying, we get

$f(x) = (x-7)^3(x+1)^2(x-5)$

That's already in factored form so we leave it here.

3 0

3 years ago

GARDENING A gardener uses a grow light to grow vegetables indoors. If m∠1=(8x)° and m∠2=(7x−4)°, what is m∠1?

labwork [276]

Give me a like bshshejsjaejke

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

3 years ago

(pic inside) What is the approximate value of the function at x = 1?

Kay [80]

Answer: -2

Step-by-step explanation:

When x = 1, y = -2.

Hope it helps <3

6 0

3 years ago

Find the total surface area of this triangular prism.

Irina18 [472]

Answer:

not sure but i think its 425 cm

Step-by-step explanation:

for the square i dont know

how its called in english the surface is 25×10= 250cm

and for the triangle its (25×14):2 = 175cm

so 175 + 250= 425cm

4 0

2 years ago