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Ksenya-84 [330]
2 years ago
12

How much more area does a large pizza with a 12 in. diameter have than a small pizza with an 8 in. diameter? Round your answer t

o the nearest square inch.
Mathematics
1 answer:
ivolga24 [154]2 years ago
4 0

Answer: About 63 in²

Step-by-step explanation:

<u>Area of circle = π · r²</u>

  • r = radius length
  • π ≈ 3.14

<u>Area of large pizza:</u>

\pi *r^{2} =3.14*6^{2} =3.14*36=113.04

<u>Area of small pizza:</u>

\pi *r^{2} =3.14*4^{2} =3.14*16=50.24

<u>Difference in area:</u>

113.04-50.24=62.8

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Addison receives $575 weekly gross pay. What can she expect to receive annually (for the year), if she works the same hours ever
Mariulka [41]

Answer:

29,900 dollars a year

Step-by-step explanation:

So first we need to find how many weeks are in a year which there are 52.143 weeks but that can be rounded to 52.  Now that we know that there are 52 weeks in a year all we have to do is multiply 52 by 575 which equals 29,900 dollars a year.

Hope this helps!

6 0
3 years ago
Factor 5(2x+7)+4(2x+7)<br>enter your answer in the box​
AfilCa [17]

Answer:

18x+63

Step-by-step explanation:

First you've to simplfy it, multiply the first bracket by 5 and the second by 4.

= (5)(2x)+(5)(7) + (4)(2x)+(4)(7)

= 10x+35+8x+28

Combine Like Terms:

= 10x+35+8x+28

= (10x+8x)+(35+28)

= 18x+63

6 0
3 years ago
Read 2 more answers
Valentino wants to estimate the product (5.2)(9.9). Which expression shows each factor rounded to the nearest whole
vovikov84 [41]

Answer:

it is (6)(10)

Step-by-step explanation:

I just took the edgenuity  test so I know

5 0
3 years ago
In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability
Pani-rosa [81]

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

  • 0.07
  • 0.56
  • 0.79
  • 0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

5 0
3 years ago
A mother decides to teach her son about a letter each day of the week. She will choose a letter from the name of the day. For ex
avanturin [10]

Answer:

Check Explanation

Step-by-step explanation:

The days of the week include

Sunday

Monday

Tuesday

Wednesday

Thursday

Friday

Saturday

a) So, the possible letters to be taught include

A, D, E, F, H, I, M, N, O, R, S, T, U, W, Y

There are indeed 15 possible letters.

These are the letters from which all the days of the week are formed from.

b) There are more than 4 letters that can't be taught using this method.

All the letters that cannot be taught using this method because no day of the week contains them include

B, C, G, J, K, L, P, Q, V, X, Z

c) In Tuesday, there are 7 distinct letters.

So, the sample space consist of 7 letters.

n(sample space) = 7

n(Y) = 1

Probability of picking a Y = (1/7)

The reasoning is simple, picking a Y on a Tuesday is one out of 7 possible outcomes, so, the probability of picking a Y on a Tuesday to teach the kid about = (1/7) = 0.143

Hope this Helps!!!

6 0
3 years ago
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