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olga55 [171]
3 years ago
13

In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability

of success of a single trial of this experiment?
Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:

0.6 is the probability of success of a single trial of the experiment

Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

  • 0.07
  • 0.56
  • 0.79
  • 0.6

Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

\mu =\frac{np}{\sigma}=\sqrt{np(1-p)}

now,

Z=\frac{X-\mu}{\sigma}

so,

by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

10.8241=27-27p

27p=27-10.8241

p=0.6

Which is the probability of success of a single trial of the experiment

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1. What is the solution of n^2-49=0?
Effectus [21]

<u>Answer:</u>

<h2>1. a</h2><h2>2. b</h2><h2>3. b</h2><h2>4. b</h2><h2>5. 22</h2>

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1.

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n=√49

n=7

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x²+64=0

x=√64

x=8

3.

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l = 12x

4.

b = (24×2)/3b

b = 48/3b

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5.

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x² = 103-z

x = √(103-z)

for x = -9 and 9    (103-z) must equal 81

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