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Alika [10]
3 years ago
13

What is the approximate volume of the cone? Use 3.14 for pi

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

157 cm cubed

Step-by-step explanation:

hope this helps!

Katyanochek1 [597]3 years ago
4 0

Answer:

157cm3

Step-by-step explanation:

V=1/3πr2h

=1/3*3.14*5*5*6

=5*5*2*3.14

=157cm3

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A fair tossed 10 times . Find the probability of obtaining (i) exactly four heads (ii) 3 heads and 7 tails (iii) at least one he
vodka [1.7K]

Answer:

0.205 ; 0.117 ; 0.999

Step-by-step explanation:

Using binomial probability distribution :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

Probability of success, p = 0.5

P(x = 4) = 10C4 * 0.5^4 * 0.5^6

P(X = 4) = 0.205078125

B.) 3 heads and 7 tails

P(X = 7) = 10C7 * 0.5^7 * 0.5^3

P(X = 7) = 120 * 0.0009765625

P(X = 7) = 0.117

P(atleast one head)

P(x greater than equal to 1) = p(x =1) +... P(x = 10)

Using a binomial probability calculator :

P(x greater than equal to 1) = 0.999

3 0
3 years ago
Write an explicit and a recursive formula for the sequence.<br> 3, 10, 17, 24, 31,
malfutka [58]
 i believe the answer would than have to be 17,24,31,45,52
6 0
3 years ago
The Foster family bought 4 crates of eggs last week . Each crate had 18 eggs . Since then , they have eaten 28 of the eggs . How
mr Goodwill [35]
There are 44 eggs left.
Work:
4x18=72
72-28=44
4 0
3 years ago
Read 2 more answers
What is the difference of 2 3/8-1 7/8
-BARSIC- [3]
2 3/8 - 1 7/8
Change to improper fractions
19/8 - 15/8 = 4/8 = 1/2
6 0
3 years ago
Read 2 more answers
What proportion of these candy bars have more than 300 calories per serving? (Round your answer to two decimal places.)
Hatshy [7]

Answer:  0.12

Step-by-step explanation:

There are 65 candy bars. Out of that;

2 candy bars have 300 to 350 calories

1 candy bar has 350 to 400 calories

4 candy bars have 400 to 450 calories

1 candy bar has 450 to 500 calories

The total proportion out of 65 candy bars that have over 300 calories is;

= ( 2 + 1 + 4 + 1) / 65

= 8/65

= 0.12

3 0
3 years ago
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