2x-1=5-6x
2x=5-6x+1
2x=-6x+6
2x+6x=6
8x=6x=6/8
x=3/4
Oh hey, its me again.
Answer:
Given coordinetes of triangle A(−2,3),B(8,3) and C(6,7)
AB=
[8−(−2)]
2
+(3−3)
2
=
(10)
2
+(0)
2
=
100
AC=
[6−(−2)]
2
+(7−3)
2
=
(8)
2
+(4)
2
=
64+16
=
80
BC=
(6−8)+[7−(2)]
2
=
(−2)
2
+(4)
2
=
4+16
=
20
If ABC is a right angled triangle, then square of one side must be equal to sum of suare of other two sides.
AB
2
=(
100
)
2
=100
and AC
2
+BC
2
=(
80
)
2
+(
20
)
2
=100
∴AB
2
=AC
2
+BC
2
thus triangle satisfies the Pythagoras theorem
Hence, the triangle is right angled triangle.
Step-by-step explanation:
F+s=95
f=s+27
s+27+s=95
2s=95-27
sixth graders = 34
fith graders = 61
The answer is 10. If you replace the number letters with the numbers you get 6 + 10 / 2 - 1. Then you follow PEMDAS, so first divide 10 with 2 to get five (6 + 5 - 1). Add 6 and 5 to get 11 and subtract 1 to get the final answer of 10.
