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lesantik [10]
2 years ago
10

Xby the power of 5 times y to the power of 6 over 2 by the power of -2 times xby the power of 0times x by the power of 9

Mathematics
1 answer:
mars1129 [50]2 years ago
8 0

Answer:

We have the sentence:

"X by the power of 5 times y to the power of 6 over 2 by the power of -2 times x by the power of 0times x by the power of 9"

Let's break it into parts.

"X by the power of 5 times y to the power of 6..."

This can be written as:

x^5*y^6

"...  2 by the power of -2 times x by the power of 0times x by the power of 9"

This can be written as:

2^(-2)*x^(0)*x^(9)

And we have the quotient between the first thing and the second thing, then the equation is:

\frac{x^5*y^6}{2^{-2}*x^0*x^9}

And any number by the power of 0 is equal to 1, then:

x^0 = 1, then we can rewrite the equation as:

\frac{x^5*y^6}{2^{-2}*x^9}

We can keep simplifying this.

We know that:

a^(-n) = (1/a)^(n)

Then:

2^(-2) = (1/2)^2 = 1/4

Then we get:

\frac{x^5*y^6}{2^{-2}*x^9} = \frac{x^5*y^6}{x^9}*4

And we also know that:

a^n/a^m = a^(n - m)

Then:

\frac{x^5*y^6}{x^9}*4 = 4*y^6*\frac{x^5}{x^9} = 4*y^6*x^{5 - 9} = 4*y^6*x^{-4} = \frac{4*y^6}{x^4}

And we can't simplify this anymore.

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Answer:

9.34%

Step-by-step explanation:

p = 4%, or 0.04

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u = Expected value = n * p = 667 * 0.04 = 26.68

SD = Standard deviation = \sqrt{np(1-p)}  =\sqrt{667*0.04*(1-0.04)} = 5.06

Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?

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1. Solve the following equation.(MAFS.8.EE.3.7)<br><br> 5(3x + 7) + 2x = 7x – 5(–2x + 9)
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Answer:

there is no solution

Step-by-step explanation:

Expand.

15x+35+2x=7x+10x-4515x+35+2x=7x+10x−45

2 Simplify  15x+35+2x15x+35+2x  to  17x+3517x+35.

17x+35=7x+10x-4517x+35=7x+10x−45

3 Simplify  7x+10x-457x+10x−45  to  17x-4517x−45.

17x+35=17x-4517x+35=17x−45

4 Cancel 17x17x on both sides.

35=-4535=−45

5 Since 35=-4535=−45 is false, there is no solution.

No Solution

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