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2 years ago

Please help me Solve for x. Have to show work

Mathematics

1 answer:

REY [17]2 years ago

6 0

A -17 3/4< x so u have to simplify-17 3/4 by multiply 17*4=68+3=71/4 so the x stands for -71/4 and it has to be 4 as the denominator because it it the denominator for the question.
B, C, D are also the same answer-17/4
And for 15 3/4<-2+ x it is also the same answer

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Four out of 12 students like chicken better than steak. What percent prefer chicken

Sauron [17]

Answer:

33.333...(%)

Step-by-step explanation:

4 divided by 12 gives you 0.333... (3 repeating)

3 0

2 years ago

George sold 18, 22, 26, 12, 25, 20, and 19 cars per month over the past seven months. He followed the steps below to

ikadub [295]

Answer:

George made the first mistake by multiplying by 7 instead of 8

Step-by-step explanation:

The total cars needed to have a mean of 24:

24 x 8 = 192

Total cars sold during the seven months:

18 + 22 + 26 + 12 + 25 + 20 + 19 = 142

Subtract the total cars sold from the total cars needed:

192 - 142 = 50

George needs to sell 50 cars in the eight month in order to have an average of 24 cars sold per month.

8 0

3 years ago

Read 2 more answers

select the polynomial that is a perfect square trinomial. 49x2 − 8x 16 4a2 − 10a 25 25b2 − 5b 10 16x2 −8x 1

Evgesh-ka [11]

16x² - 8x + 1 = (4x)² - 2 · 4x · 1 + 1² =(4x - 1)²

Used: (a - b)² = a² -2ab + b²

8 0

3 years ago

Read 2 more answers

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

5 0

2 years ago

Jess observed that 60% of the people at a mall on a particular day shopped for clothes. If 2500 people at the mall did not shop

GalinKa [24]

2500 is 40% of the 100%
so, from the 40%, figure out 10%
2500/4=600
600 x 6=3,600
so, 3,600 is the answer

7 0

2 years ago