In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
The value of x is 23.
Simply find the scale factor or what was used to dilate △MAH to produce △WCF.
Use the equation copy over the original,

Reduce,

So our scale factor is ¼ or 0.25
So if we use it and multiply the corresponding side of the missing side with the original we get,

Therefore 23 is our missing side! !
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I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
Answer:
a = 1 b = -1.
Step-by-step explanation:
Suppose the quotient when you divide x^4+x^3+ax+b by x^2 + 1 is
x^2 + ax + b then expanding we have:
(x^2 + 1)(x^2 + ax + b)
= x^4 + ax^3 + bx^2 + x^2 + ax + b
= x^4 + ax^3 + (b + 1)x^2 + ax + b Comparing this with the original expression:
x^4 + x^3 + 0 x^2 + ax + b Comparing coefficients:
a = 1 and b+ 1 = 0 so b = -1.
Answer:
80%
Step-by-step explanation:
Please consider the complete question:
Micah is preparing for a piano recital. He practices for 50 minutes on Monday and 90 minutes on Wednesday. By how much did she increase the time she practiced each day?
We will use percent change formula to solve our given problem.

Upon substituting our given values, we will get:



Therefore, Micah had increased the time by 80%.