It would equal 5.20043337 but rounded to the tenths would be 5.2 I think
Here's our equation.

Let's reorder this so t² comes before t.

We want to find out when the ball hits the ground. Essentially, <em>what is t when h=0?</em>
Let's plug in 0 for h and solve.

From here we can use a number of methods to solve.
Methods such as splitting the middle, quadratic formula, etc. are not necessary for this equation, however. The best method here is just plain factoring.
-16t² and 176t are both divisible by 16t.

Now we want t to equal zero. If either of those factors were zero, then the whole thing would be zero when we multiply by it. The first option is obvious. If t were 0, 16t would be 0. That's when the ball is first kicked off the ground. The other, 11-t, works out to be
t = 11.
Answer:
A
Step-by-step explanation:
You divide the diameter by 2 to get radius. So 5÷2=2.5
So then you multiply 2.5 by pi aka 3.14 so 2.5x3.14=7.85 So we rounds 7.85 to 7.9
There is 1 solution x=-10