SOLUTION
Let us use a simple diagram to interprete the question
In the diagram above, the dark stuff below represents the shadow and the rectangular bar represents the building. I have labelled the height of the building as h.
So we will use the right-angled triangle formed to find h
As we can see h represents the opposite side and 56.5 feet represents the adjacent side of the right-angle triangle. So we will use TOA

So we have

Hence the answer is 104.9 feet to the nearest tenth
Answer:
62°
Step-by-step explanation:
There should be 180° in a straight line.
63+55=118.
180-118=62
My deepest apologies if it is incorrect.
Solve out
x^2 + 64 = 0
x^2 = -64 ( we are going to use imaginary numbers to solve)
x =

x = 8i, -8i final answers
Answer




Explanation:
Given
See attachment for proper data presentation
--- Sample
A = Supplier 1
B = Conforms to specification
Solving (a): P(A)
Here, we only consider data in sample 1 row.
Here:
and 



P(A) is then calculated as:



Solving (b): P(B)
We only consider data in the Yes column.
Here:
and 



P(B) is then calculated as:



Solving (c): P(A n B)
Here, we only consider the similar cell in the yes column and sample 1 row.
i.e. [Supplier 1][Yes]
This is represented as: n(A n B)

The probability is then calculated as:



Solving (d): P(A u B)
This is calculated as:

This gives:

Take LCM


