3 years ago

PH is the midsegment of Triangle KLM. Find the value of x.

Mathematics

1 answer:

Gnoma [55]3 years ago

7 0

Answer:

x = 26

Step-by-step explanation:

The midsegment is parallel to the side KM and half its length, thus

KM = x = 2 × 13 = 26

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-Dominant- [34]

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What is the directrix of the parabola defined by `(1)/(4)(y + 3) = (x − 2)^2`? A. `y = -(49)/(16)` B. `x = -(49)/(16)` C. `y = (

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In trapezoid $ABCD$, $\overline{AB}$ is parallel to $\overline{CD}$, $AB = 7$ units, and $CD = 10$ units. Segment $EF$ is drawn

Mekhanik [1.2K]

Answer:

EF = 58/7

Step-by-step explanation:

If you extend both BC and AD to meet at P you get 3 similar triangles PAB, PEF, and PCD. Let's call BF = 3x and FC = 4x. Therefore the following proportions can be expressed:

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3 years ago

Please please help me!!!!!

Tamiku [17]

Your just multiplying 7 and 10, so your answer is gonna be B.

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