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kvasek [131]
4 years ago
13

Describe the graph of the equation x = 3

Mathematics
1 answer:
DochEvi [55]4 years ago
4 0
Straight up and down at (3,0)
Slope is undefined.
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What is the slope-intercept equation of the line shown below? (3,4) (-3,-2)
AysviL [449]
Find the gradient
m = y2-y1 / x2-x1
m = 4-(-2) / 3-(-3)
m = 6 / 6
m = 1

Insert the values of one of the points into y=mx+c to find c (choosing point (3,4)):
y = mx + c
4 = 1(3) + c
c = 4 - 3
c = 1

Therefore, the equation is:
y = x + 1
6 0
4 years ago
What is the slope of y = 4x and what does this mean?
tatuchka [14]
Y=4 when X=1
So it mean y=4(1)
Y=4
X equal 1 when they don't give you the number
8 0
3 years ago
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What is the slope of the graph? please help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
nignag [31]

Answer:

The slope of the graph is 3/5

Step-by-step explanation:

We know that slope is nothing but rise over run. In this equation, the spacing is 3 points different vertically and 5 horizontally. If we do Rise Over Run, we will get 3/5 as our answer.

5 0
3 years ago
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The distance of planet Jupiter from the Sun is approximately 7.8 ⋅ 108 kilometers, and the distance of planet Saturn from the Su
katen-ka-za [31]
Distance of Jupiter to sun:
7.8*108=842.4
Distance of Saturn from sun:
1.5*109=163.5

difference:
842.4-163.5=678.9
6 0
4 years ago
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A flea jumps from the ground to a height of 30 cm and travels 15 cm horizontally from where it started. Suppose the origin is lo
adelina 88 [10]

Answer:

y=-\frac{8}{15}x^2+8x

Step-by-step explanation:

Consider the equation that shows flea's motion is y=ax^2+bx+c.

Since the origin is located at the point from where the flea jumped,

So, y=ax^2+bx+c  passes through (0,0).

That is, (0,0) must satisfy y=ax^2+bx+c,

0=a(0)^2+b(0)+c

\implies c =0

Now, it travels 15 cm horizontally from where it started.

That is, y=ax^2+bx+c  passes through (15,0).

0=a(15)^2+b(15)+c

0=a(225)+b(15)   (Because c=0)

225a+15b=0  ...... (1)

Again, it jumps from the ground to a height of 30 cm,

So, the y-coordinate of vertex of y=ax^2+bx+c is 30.

Now, the x-coordinate of vertex of the quadratic function must be half of the distance from its starting point to final point.

That is, x-coordinate of the vertex = \frac{15}{2} = 7.5,

Thus, vertex = (7.5, 30)

(7.5, 30) must satisfy y=ax^2+bx+c

That is, 30=a(7.5)^2+b(7.5)+c

30=56.25a+7.5b

56.25a+7.5b=30                ...... (2)

Equation (1) - 2 × equation (2),

225a - 112.5a = -60

112.5a = -60

\implies a = -\frac{60}{112.5}=-\frac{8}{15}

From equation (1),

225(-\frac{8}{15})+15b = 0

-120+15b=0

15b=120

b=8

Substitute the values of a, b and c in the quadratic equation y=ax^2+bx+c,

y=-\frac{8}{15}x^2+8x

Which is the required quadratic equation.

6 0
3 years ago
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