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2 years ago

Find X, and the two angle measures.

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

5 0

Answer:

x = -4

m<LMP = 77°

m<NMP = 103°

Step-by-step explanation:

Straight angles by definition have a total measure of 180°.

This means that m<LMP and m<NMP are 180° together.

Therefore m<LMP + m<NMP = 180°.

[substitution property]

(-16x + 13)° + (-20x + 23)° = 180°

[associative property of addition]

(-36x + 36)° = 180°

-36x + 36 = 180

–36 –36

-36x = 144

÷-36 ÷-36

x = -4

_________________

Since m<LMP = (-16x + 13)°.

Using substitution with x = -4:

m<LMP = (-16(-4) + 13)° = (64 + 13)° = 77°.

Since m<NMP = (-20x + 23)°.

Using substitution with x = -4:

m<NMP = (-20(-4) + 23)° = (80 + 23)° = 103°.

This is true because 77° + 103° = 180°.

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Two angles are supplementary. If the m∠A is five times the sum of the m∠B plus 7.2°, what is m∠B?

user100 [1]

Answer:

36 i think

Step-by-step explanation:

4 0

3 years ago

To win the carnival game Ring Ding, you must toss a wooden ring onto a grid of rectangles so that it lands without touching any

guapka [62]

Answer:

5in x 10in

Step-by-step explanation:

Solution:

1. You have to assume that the ring will land on the board and as a result, just focus on one rectangle of the board since they are all the same size.

2. For the ring to land entirely inside the rectangle, the center of the ring needs to be 1.5 inches inside the border (radius is 1.5 inches), so the "winning rectangle" will have dimensions:

L = (x - 2(1.5)) = x - 3

w = (2x - 2(1.5)) = 2x-3.

3. Now, we will set up and solve our geometric probability equation. The winning rectangle's area of (x-3)*(2x-3) divided by the total rectangle's area of x*(2x) = 28%

(2x-3)*(x-3)/(2x^2) = .28

2x^2 - 9x + 9 = .56x^2

1.44x^2 - 9x + 9 = 0

4 . Now you can plug that in the quadratic formula and get the solutions x = 1.25 or 5. However, it cannot by 1.25 because that is too small of a dimension for the the circle with diameter of 3 to fit in, the answers has to be 5.

5. As a result, the dimensions of the rectangles are 5in x 10in.

6 0

3 years ago

A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo

Arada [10]

Answer:

The parabolic shape of the door is represented by $y - 32 = -\frac{2}{49}\cdot x^{2}$ . (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

$y - k = C \cdot (x-h)^{2}$

Where:

$h$ - Horizontal component of the vertix, measured in inches.

$k$ - Vertical component of the vertix, measured in inches.

$C$ - Parabola constant, dimensionless. (Where vertix is an absolute maximum when $C < 0$ or an absolute minimum when $C > 0$ )

For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

$V (x,y) = (0, 32)$ (Vertix)

$A (x, y) = (-28, 0)$ (x-Intercept)

$B (x,y) = (28. 0)$ (x-Intercept)

The following equation are constructed from the definition of a parabola:

$0-32 = C \cdot (28 - 0)^{2}$

$-32 = 784\cdot C$

$C = -\frac{2}{49}$

The parabolic shape of the door is represented by $y - 32 = -\frac{2}{49}\cdot x^{2}$ . Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

$y -32 = -\frac{2}{49} \cdot x^{2}$