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Tanzania [10]
3 years ago
11

What have you liked and disliked about being virtual this school year? Do you plan to be virtual next semester? can someone whri

te summary i lost my dog we are trying to find n i need to dis homework i can not come up with something i am really sad i will you brainlsist thank you​
Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0

Answer:

I don't like not being able to see my friends and miss seeing my teachers and don't do as well. I also struggle when i cant be face to face with a teacher so I can get help. I liked not having to wear a mask and chill at home in my pajamas. I also do not plan to be virtual next semester.

Step-by-step explanation:

Pls give me brainliest

Murrr4er [49]3 years ago
3 0

To be honest I have not liked anything about being online at school, I hope to return soon (but I am a little scared because I am new to school and I have no friends: c) If the next semester they open I plan to go to schools, but if they don't open, then I'll stay online. I hope they find your pet soon! I don't know you but I love you very much!

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For our sample of student's measurements we expect that 68% of the values to fall within one σ (0.23mm) from our mean davg (21.0
7nadin3 [17]

Answer: 74.5% of the measurements fall within one standard deviation of the average.

Step-by-step explanation:

The total number of measurements given is 2 + 12 + 10 + 33 + 40 + 76 + 80 + 65 + 52 + 22 + 12 + 5 + 11 = 420

If the mean is 21 mm and one standard deviation is 0.23 mm, then one standard deviation from the mean would be

21 ± 0.23

The lower limit is 20.77 mm

The upper limit is 21 + 0.23 = 21.23 mm

The number of measurements that fall within this range are

20.8 × 40

20.9 × 76

21.0 × 80

21.1 × 65

21.2 × 52

The total number of measurements that fall within this range is

40 + 76 + 80 + 65 + 52 = 313

The percentage of the measurements that fall within one standard deviation of the average is

313/420 × 100 = 74.5%

8 0
3 years ago
substitute the given values into the given formula and solve for the unknown variable. If necessary, round to one decimal place.
Valentin [98]
I= PRT
7280=26000×0.07T
7280\1820=1820T\1820
4=T
dats all
7 0
4 years ago
Question 3 (1 point)
Bogdan [553]

Answer:

The war was primarily fought over contested claims between the British and French over the land of the Ohio Country.

Step-by-step explanation:

So, I guess, land ownership or settlements.

3 0
3 years ago
Is this right? Please help me.​
Tpy6a [65]

Answer:

I think so

Step-by-step explanation:

7 0
3 years ago
An equilateral triangle has an altitude length of 36 feet. Determine the length of a side of the triangle.
liq [111]
\bf \textit{height of an equilateral triangle}\\\\
h=\cfrac{s\sqrt{3}}{2}\quad 
\begin{cases}
s=\textit{length of a side}\\
---------\\
h=36
\end{cases}\implies 36=\cfrac{s\sqrt{3}}{2}
\\\\\\
72=s\sqrt{3}\implies \cfrac{72}{\sqrt{3}}=s~~\stackrel{rationalizing~it}{\implies }~~\cfrac{72}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{7\sqrt{3}}{3}
3 0
3 years ago
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