<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B3%7D%20%20%5Ctimes%20%20%7Bx%7D%5E%7B4%7D%20" id="TexFormula1" title=" {x}^{3}

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dybincka [34]

4 years ago

\times {x}^{4} " alt=" {x}^{3} \times {x}^{4} " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Fantom [35]4 years ago

8 0

Answer:

$x^{7}$

Step-by-step explanation:

$x^{n}$ × $x^{m} = x^{n+m}$

Naddika [18.5K]4 years ago

3 0

Answer:

$x^{7}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$ , thus

x³ × $x^{4}$ = $x^{(3+4)}$ = $x^{7}$

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klemol [59]

Using it's concept, the approximate perimeter of pentagon ABCDE is given as follows:

34.4 units.

<h3>What is the perimeter of a figure?</h3>

The perimeter of a figure is given by the sum of the lengths of it's outside dimensions.

In this problem, the vertices are in a coordinate-plane, hence the distances are found using the formula for the distance between two points.

<h3>What is the distance between two points?</h3>

Suppose that we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

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The length of segment BC is:

$BC = \sqrt{(6 - 3)^2+(0 + 4)^2} = 5$

The length of segment CD is:

$CD = \sqrt{(-3 -3)^2+(-4 + 4)^2} = 6$

The length of segment DE is:

$DE = \sqrt{(-6 + 3)^2+(0 + 4)^2} = 5$

The length of segment EA is:

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Hence the perimeter is:

P = AB + BC + CD + DE + EA = 9.2 + 5 + 6 + 5 + 9.2 = 34.4 units.

More can be learned about the perimeter of a figure at brainly.com/question/18610622

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2 years ago

Solve for s 2-2s=3/4s+13

lozanna [386]

Consolidate (group together) the s terms and then do the same thing to the constant terms:

-2s - (3/4)s = 13 - 2
11
Then (-2 3/4)s = 11, and s = ---------------- = -4 (answer)
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I have a feeling that the answer 170 in.

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