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alexgriva [62]
4 years ago
7

Create or find your own, unique function h(x). discuss the limit of your function as latex: x x approaches some particular value

, let's say a, where the limit exists but the y-value does not or is different than the limit.
Mathematics
1 answer:
Zina [86]4 years ago
6 0
Consider the function:

h(x)= \frac{x^2-1}{x-1}

As x tends to 1, 

h(1)= \frac{1^2-1}{1-1} = \frac{0}{0}

hence, the y value does not exist.

But

\lim_{x\to1} h(x)= \lim_{x\to1}  \frac{x^2-1}{x-1}  \\  \\ = \lim_{x\to1} \frac{(x-1)(x+1)}{x-1}= \lim_{x\to1} (x+1) \\  \\ =1+1=2

Therefore, the limit of h(x) exists but the y-value does not exist.
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Find the value of x when 6-4x = 6x-8x-2.
mestny [16]

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4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6−4x=6x−8x−2

6+−4x=6x+−8x+−2

−4x+6=(6x+−8x)+(−2)(Combine Like Terms)

−4x+6=−2x+−2

−4x+6=−2x−2

Step 2: Add 2x to both sides.

−4x+6+2x=−2x−2+2x

−2x+6=−2

Step 3: Subtract 6 from both sides.

−2x+6−6=−2−6

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Step 4: Divide both sides by -2.

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here is a link:

https://www.mathpapa.com/algebra-calculator.html?q=6-4x%3D6x-8x-2.

6 0
4 years ago
7x+6= 5(x+2)<br>help me​
Zigmanuir [339]

\huge \pink{solution}

Given :7x+6=5(x+2)

Now We will use the distributive property to multiply 5 by x+2.

→7x+6=5x+10

We will Subtract 5x from both sides.

→7x+6−5x=10

We will Combine 7x and −5x to get 2x.

→2x+6=10

We will Subtract 6 from both sides.

2x=10−6

We will Subtract 6 from 10 to get 4.

2x=4

We will Divide both sides by 2.

x= 4/2

At last,We Divide 4 by 2 to get 2.

x=2

7 0
3 years ago
Read 2 more answers
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