All categories

3 years ago

Which graph represents the solution set of the inequality 11 ≤ 2x + 5 ≤ 15

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

Answer:

Step-by-step explanation:

First, simply the inequality.

$11\leq 2x+5\leq 15\\6\leq 2x\leq 10\\3\leq x\leq 5$

Based on the simplified inequality, you are looking for a line with closed points on 3 and 5. Therefore, the answer is D.

You might be interested in

<img src="https://tex.z-dn.net/?f=p%5E%7B3%7D%20at%20%5C%5C%5C%5C%20p%20%3D%202" id="TexFormula1" title="p^{3} at \\\\ p = 2" al

WITCHER [35]

<h3>Answer: 8</h3>

Reason:

Replace p with 2 and evaluate.

$p^3 = 2^3 = 2*2*2 = 8$

Think of a cube that is 2 units along each side. It's volume is 2*2*2 = 8 cubic units. Repeated multiplication can be shortened to using exponents.

Another example: $7^4 = 7*7*7*7$

6 0

2 years ago

a classroom has triangular tables there is enough space at each side of a table to seat one child the tables in this class are a

Gekata [30.6K]

Answer:

Step-by-step explanation:

3 students can fit in one table. 5*3=15

5 0

2 years ago

6.<br> Find the slope of a line that contains the points: (-3,5) and (-1, 12).<br> Slope =

kap26 [50]

Answer:

7/2

Step-by-step explanation:

Slope= y2-y1/x2-x1

(12-5)/(-1--3)

-> (7)/(2)

7/2

6 0

3 years ago

If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes

anyanavicka [17]

ANSWER

$x = 2 \: \: or \: \: x = 15$

$x = - 2 \: \: or \: \: x = - 15$

EXPLANATION

The given polynomial is

$f(x) = {x}^{2} + kx + 30$

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

$m + n = - \frac{b}{a} = -k$

and the product of roots is

$mn = \frac{c}{a} = 30$

The square difference of the zeroes is given by the expression.

$( {m - n})^{2} = {(m + n)}^{2} - 4mn$

From the question, this difference is 169.

This implies that:

$( { - k)}^{2} - 4(30) = 169$

${ k}^{2} -120= 169$

$k^{2} = 289$

$k= \pm \sqrt{289}$

$k= \pm17$

We substitute the values of k into the equation and solve for x.

$f(x) = {x}^{2} \pm17x + 30$

$f(x) = (x \pm2)(x \pm 15)$

The zeroes are given by;

$(x \pm2)(x \pm 15) = 0$

$x = \pm2 \: \: or \: \: x = \pm 15$

5 0

3 years ago

Find the length of<br> __<br> JK<br> Round answer to nearest tenth.

PIT_PIT [208]

Answer:

Step-by-step explanation:

We would apply the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes

JK² = JL² + KL² - 2(JL × KL)Cos10

JK² = 61² + 53² - 2(61 × 53)Cos10

JK² = 3721 + 2809 - 6466Cos10

JK² = 6530 - 6367.767

JK² = 162.233

Taking square root of both sides of the equation, it becomes

JK = √162.233

JK = 12.73 to the nearest tenth

6 0

3 years ago