Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
13-9 = 4
4-4 = 0
0 divided by 2 = 0
2x = 0
x = 0
Answer:
2 x 2 x 2 x 2 x 2 x 5 x 13
Step-by-step explanation:
The Prime Factorization is:
2 x 2 x 2 x 2 x 2 x 5 x 13
In Exponential Form:
25 x 51 x 131
CSV Format:
2, 2, 2, 2, 2, 5, 13
