The idea is to use the zero product property in reverse to go from the roots to the factorization. Then you expand out the polynomial using the distributive property.
x = 5 or x = 7 or x = -8
x-5 = 0 or x-7 = 0 or x+8 = 0
(x-5)(x-7)(x+8) = 0
(x-5)(x^2+x-56) = 0
x(x^2+x-56) - 5(x^2+x-56) = 0
x^3+x^2-56x -5x^2-5x+280 = 0
x^3-4x^2-61x+280 = 0
f(x) = x^3 - 4x^2 - 61x + 280
<h3>Answer: Choice D</h3>
Answer:
sorry I can't help you because the diagram is not there and I can't get the answer without it
Hey there. So basically, find out how much the pencils and notebooks cost first.
The notebooks cost = $3.25
The pencils cost = $0.50
Then, think about what you need to figure out in this problem.
Jake has $20. You need to find how many notebooks Jake can buy in maximum after buying 8 pencils.
If Jake buys 8 pencils that costs $0.50 each, he spends $4 on the pencils.
So now, to find out how many notebooks he can buy, do 20 minus 4.
Jake's got $16 left.
If the notebooks cost $3.25 each, we need to find out how many notebooks he can buy by dividing them. So, 16 divided by 3.25 equals 4.923... and so on.
That means, Jake can buy 4 notebooks with his remaining money.
Answer:
X=2/5,8/3
Step-by-step explanation:
Look on Tiger Algebra for step by step. JUst put the problem into g-oogle.
Answer:
1. 4x = 15
2. 4(n - 3) = 24
3. 2n + 5 = 13
4. (3/4)n = 9
5. 6x - 4 = 8
Step-by-step explanation:
this should be correct. hope this helps!
