You knew where to place the target based on the coordinates (-5,4). Starting from the origin (0,0), we know how many units to move to horizontally and vertically. We move the target 5 units to the left, because it is negative. We move the target 4 units up, because it is positive. (x,y)
w x L = 36
w = L- 5
L x ( L-5 ) = 36
L^2 -5L -36 =0
<span>Use the quadratic formula
L= - b + radical b^2 - 4 (a)(c) divided 2.a
L= 5 + 13 / 2 = 18 /2 =9</span>
The solutions for ‘x’ are 2 and -5
<u>Step-by-step explanation:</u>
Given equation:

Since the base on both sides as ‘12’ are the same, we can write it as



Often, the value of x is easiest to solve by
by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.
<u>The Quadratic Formula:</u> For
, the values of x which are the solutions of the equation are given by:

Where, a = 1, b = 3 and c = -10



So, the solutions for ‘x’ are


The solutions for ‘x’ are 2 and -5
The slope would go vertically starting it at 5. you place your dot at 5 and draw a line going up and down throughout both the top and bottom of the right side of the graph. hope it helped