Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.
This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.
34 in - 31.2 in
The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
1.9
32 in - 31.2 in
and that to the left of 32 in is z = ---------------------- = 0.421
1.9
Know how to use a table of z-scores to find these two areas? If not, let me know and I'll go over that with you.
My TI-83 calculator provided the following result:
normalcdf(32, 34, 31.2, 1.9) = 0.267 (answer to this sample problem)
Answer:B
Step-by-step explanation: hopes this helps
Height of tree is given by the distance multiplied by the tangent of the angle of elevation:
Height = 30*tan(40) = 30(0.8391)=25.17 ft
Answer:it is
Step-by-step explanation:
Answer:
B.) No, the power multiplied to 8.64 should have an exponent of 0.
Step-by-step explanation:
took the test on Edgenuity and got it right! Hope this helps and please mark brainliest if can.
