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umka21 [38]
2 years ago
6

The moon forms a right triangle with the Earth and the Sun during one of its phases, as shown below: A right angle triangle is s

hown with the Earth at the right angle. The acute angle between the line joining the Earth and the S The moon is, on average 238,900 miles from the Earth and the Sun is roughly 93,000,000 miles from the Earth. What is the measure of angle x? Round to the nearest hundredth. Note. This is a very small angle.
Mathematics
2 answers:
Savatey [412]2 years ago
7 0

Answer:

0.15

Step-by-step explanation:

Using trigonometry :

Tanθ = opposite / Adjacent

Opposite = distance between earth and sun = 238,900

Adjacent = distance between earth and moon = 93,000,000

Tanx = 238900 / 93000000

Tanx = 0.0025688

x = tan^-1 (0.0025688)

= 0.1471820°

Crank2 years ago
4 0

Answer:

0.15

Step-by-step explanation:

Took the test.

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5 0
2 years ago
Find the value of 10! / (10-2) !
Gnesinka [82]

Answer:

90

Step-by-step explanation:

10! / (10 - 2)!

=10!/8!

=10 * 9 * 8! /8!

=90 * 8!/8!

90

Hope this helps. Please mark as brainliest if possible. Have a nice day

3 0
3 years ago
The Venn diagram shows the results of two events resulting from rolling a number cube.
tankabanditka [31]

Answer:

P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{1}{3}

P(A) =\frac{2}{3}

P(B) =\frac{1}{2}.

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

P(A) = \frac{4}{6} = \frac{2}{3}

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

P(B) = \frac{3}{6} = \frac{1}{2}.

Now

P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}

P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}

6 0
3 years ago
Different sizes of ribbon need to be cut to go around various shapes. All of the following sizes are in inches.
LuckyWell [14K]
The decimal approximations are:

The square root of 5 is about 2.2
The square root of 8 is about 2.8
pi is about 3.14
2 square roots of 5 are about 4.4

The numbers are also placed in order from least to greatest.
8 0
3 years ago
Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
2 years ago
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