Y=-4(x-2)2+4 what is the x intercept

Mathematics

1 answer:

valentina_108 [34]3 years ago

3 0

<h2>Solving for the x-intercepts of a Parabola given the Equation</h2><h3>Answer:</h3>

$x = 3$ and $x = 1$

<h3>Step-by-step explanation:</h3>

$x$ -intercepts are just the values $x$ when $y = 0$ .

Solving for $x$ :

$0 = -4(x -2)^2 +4 \\ -4(x -2)^2 +4 = 0 \\ -4(x -2)^2 = -4 \\ 4(x -2)^2 = 4 \\ (x-2)^2 = \frac{4}{4} \\ (x -2)^2 = 1 \\ x-2 = \pm \sqrt1 \\ x -2 = \pm 1 \\ x = \pm 1 +2$

Solving for the Positive Square Root:

$x = 1 +2 \\ x = 3$

Solving for the Negative Square Root:

$x = -1 +2 \\ x = 1$

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