Question

Y=-4(x-2)2+4 what is the x intercept

Answer 1

Solving for the x-intercepts of a Parabola given the Equation

Answer:

$x = 3$ and $x = 1$

Step-by-step explanation:

$x$-intercepts are just the values $x$ when $y = 0$.

Solving for $x$:

$0 = -4(x -2)^2 +4 \\ -4(x -2)^2 +4 = 0 \\ -4(x -2)^2 = -4 \\ 4(x -2)^2 = 4 \\ (x-2)^2 = \frac{4}{4} \\ (x -2)^2 = 1 \\ x-2 = \pm \sqrt1 \\ x -2 = \pm 1 \\ x = \pm 1 +2$

Solving for the Positive Square Root:

$x = 1 +2 \\ x = 3$

Solving for the Negative Square Root:

$x = -1 +2 \\ x = 1$