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3 years ago

Can someone PLEASE help me. I really don't know...

Mathematics

1 answer:

lyudmila [28]3 years ago

3 0

Hope this helps...feel free to ask for any help

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Determine the quadratic function f whose graph is given. The vertex is (1,-3) and y-intercept is -2

Nesterboy [21]

Answer:

Vertex form: $f(x)=(x-1)^2-3$

Standard form: $f(x)=x^2-2x-2$

Step-by-step explanation:

A quadratic function in vertex form is $f(x)=a(x-h)^2+k$ where $(h,k)$ is the vertex.

We are given $h=1,k=-3$ .

Let's plug that in:

$f(x)=a(x-1)^2-3$ .

Now let's find $a$ .

We will use the $y$ -intercept $(0,-2)$ to find $a$ .

$f(0)=a(0-1)^2-3$

$-2=a(0-1)^2-3$

$-2=a(-1)^2-3$

$-2=a(1)-3$

$-2=a-3$

$1=a$

So the function in vertex form is:

$f(x)=(x-1)^2-3$ .

In standard form, we will have to multiply and combine any like terms.

Let's do that:

$f(x)=(x-1)(x-1)-3$

$f(x)=x^2-x-x+1-3$

$f(x)=x^2-2x-2$

5 0

3 years ago

Trevor solved the system of equations below. What mistake did he make in his work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 − 2

Arturiano [62]

$2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
\boxed{5x=0} \Leftarrow \hbox{the mistake, it should be 5x=20} \\
x=0 \\ \\
2(0)+y=5 \\
y=5$

If 2x+y=5, then y=5-2x, so he substituted 5-2x correctly.
x+4x=5x, so he combined like terms correctly.
If 5x-10=10, then 5x=10+10 -> 5x=20, so he subtracted 10 from the right side instead of adding 10 to the right side.

The answer is C.

Here's the correct solution:
$2x+y=5 \\
x-2y=10 \\ \\
y=5-2x \\
x-2(5-2x)=10 \\
x-10+4x=10 \\
5x-10=10 \\
5x=10+10 \\
5x=20 \\
x=\frac{20}{5} \\
x=4 \\ \\
y=5-2x \\
y=5 - 2 \times 4 \\
y=5-8 \\
y=-3 \\ \\
(x,y)=(4,-3)$

5 0

3 years ago

I am between 24 and 34 . you say my name when you count by twos from zero. you say my name when you count by fives from zero. wh

jonny [76]

The answer is 30

2 * 15 = 30
5 * 6 = 30
30 is between 24 and 34

4 0

2 years ago

I need to know How to solve it

dezoksy [38]

SohCahToa
Heard of it?
Sine- opposite over hypotenuse
Cosine-adjacent over hypotenuse
Tangent- opposite over adjacent

4 0

3 years ago