Question

PLEASE HELP!!!!!

Answer 1

Answer:

$\frac{n+2}{8}$ has a remainder of 7 ⇒ B

Step-by-step explanation:

In m ÷ n = c + $\frac{r}{n}$ ,

• m is the dividend

• n is the divisor

• c is the quotient

• r is the remainder

• m = (n × c) + r

Let us use the facts above to solve the question

∵ $\frac{n}{8}$ has a remainder of 5

→ Let us find the first number divided by 8 and give a reminder of 5

  that means let the quotient = 1

∵ n = (8 × 1) + 5 = 8 + 5

∴ n = 13

∵ $\frac{n+x}{8}$ has a remainder of 7

→ Let us find the first number divided by 8 and give a reminder of 7

  that means let the quotient = 1

∵ n + x = (8 × 1) + 7 = 8 + 7

∴ n + x = 15

∵ n = 13

∴ 13 + x = 15

→ Subtract 13 from both sides

∴ 13 -13 + x = 15 - 13

∴ x = 2

∴ $\frac{n+2}{8}$ has a remainder of 7