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7nadin3 [17]
3 years ago
12

John bought a car for $8,000. After one year the car depreciates in value

Mathematics
1 answer:
Bad White [126]3 years ago
6 0

Your answer will be 7,040.

<em>HOW TO SOLVE: </em>We start out with the car's value of 8,000. You see that the value of the vehicle is going to <em>depreciate, </em>or lower. It will depreciate by 12%, so we need to find 12% of 8,000.

This will you get you 960. All we need to do now is subtract 960 from 8,000, so you will be left with 7040.

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Ben buys a car for $50,000. The value of the car decreases at a rate of 4% per year. How much will the car be worth in 3 years?
lara31 [8.8K]
Given that the value of $50000 car decreases by 4%  per year, the value after 3 years will be given by exponential form:
y=abˣ
where:
a=initial value
b=decreasing rate
x=time in years
from the information:
a=50000, b=0.96, x=3
thus
y=50000(0.96)³
simplifying we get:
y=$44, 236.8
~$44237

Answer:
<span>B. $44,237</span>
6 0
4 years ago
Ms Smith wants to tip 15% on a bill of $35. What is the total bill
anygoal [31]

Answer:

40.25

Step-by-step explanation:

multiple 35 by 1.15

3 0
3 years ago
Can someone help me with this. Will mark brainliest. Thank you.
Butoxors [25]

Answer:

∠SVU = 49°

Step-by-step explanation:

∠SVU is an inscribed angle and arc SU is the arc it intercepts

If you didn't know an inscribed angle is equal to half the measure of its intercepted arc.

Hence ∠SVU = arc SU / 2

if arc SU = 98

Then ∠SVU = 98/2 = 49

8 0
3 years ago
The heights of a certain population of corn plants follow a normal distribution with mean 145 cm and stan- dard deviation 22 cm
Firdavs [7]

Answer with explanation:

Given : The heights of a certain population of corn plants follow a normal distribution with mean \mu=145\ cm and standard deviation \sigma=22\ cm

a) Using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponds to x= 135 will be

z=\dfrac{135-145}{22}\approx-0.45

At x= 155, z=\dfrac{155-145}{22}\approx0.45

The probability that plants are between 135 and 155 cm tall :-

P(-0.45

Hence, 34.73% of the plants are between 135 and 155 cm tall.

b) Sample size : n= 16

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponds to x= 135 will be

z=\dfrac{135-145}{22}{\sqrt{16}}\approx-1.82

At x= 155, z=\dfrac{155-145}{22}{\sqrt{16}}\approx1.82

The probability that plants are between 135 and 155 cm tall :-

P(-1.82

Hence,The percentage of the samples would the sample mean height be between 135 and 155 cm.= 93.12%  

4 0
3 years ago
Can someone please help?
algol [13]

Answer:

The one all the way to the right

Step-by-step explanation:

30 ÷ X = 6

30 ÷ 5 = 6

5 0
3 years ago
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