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alexandr402 [8]
3 years ago
12

Find the missing length indicated. X=

Mathematics
1 answer:
goblinko [34]3 years ago
5 0

Answer:

128

Step-by-step explanation:

64*2= 128

Your answer should be 128.

I hope you understand my horrible explnation.

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(x+1)^2+(x-1)^2-2x(x+2)=0
antoniya [11.8K]

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

  • (x+1)^2+(x-1)^2-2x(x+2)=0
  • x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0
  • (x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0
  • -4x + 2 = 0

Step 2: Subtract 2 from both sides.

  • -4x + 2 - 2 = 0 - 2
  • -4x = -2

Step 3: Divide both sides by -4.

  • \frac{-4x}{-4} = \frac{-2}{-4}
  • x = \frac{1}{2}
8 0
2 years ago
What is the m Angle of 1? A, B, C, D?
kari74 [83]

Answer:

pic?

Step-by-step explanation:

3 0
2 years ago
Find three consecutive even integers, such that
SIZIF [17.4K]

Answer:

8,10 ,12

Step-by-step explanation:

x

x+2

x+4

    5x-18 =x+2 + x+4

5x-18=2x+6

3x=24

x=8

   8*5=40   40-18= 22

   10+12 = 22

7 0
3 years ago
Look down below for question:
ale4655 [162]
Area of ABC : AB*AC/2

the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)

C is the second root (x-intersect), which we can find :

determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=\frac{-4-\sqrt{4(4+C)}}{-2}=2+\sqrt{4+C}

Hence the area of the triangle is AB*AC/2=(4+C)*(2+\sqrt{4+C}-2)/2=(4+C)\sqrt{4+C}/2=32 hence (4+C)\sqrt{4+C}=64 .

We remark that 64=16*4=16*\sqrt{16}

Hence 4+C=16 thus C=12

5 0
3 years ago
Abby's cat weighs 18 pounds. Her dog weighs 2 pounds more than half her cat's weight.write and evaluate an expression to show ho
Andrews [41]

Answer:

11 pounds

Step-by-step explanation:

Just divide the cats weight by 2 and then add 2

(18)/2 + 2

7 0
3 years ago
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