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2 years ago

(x+1)^2+(x-1)^2-2x(x+2)=0

Mathematics

1 answer:

antoniya [11.8K]2 years ago

8 0

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

$(x+1)^2+(x-1)^2-2x(x+2)=0$
$x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0$
$(x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0$
$-4x + 2 = 0$

Step 2: Subtract 2 from both sides.

$-4x + 2 - 2 = 0 - 2$
$-4x = -2$

Step 3: Divide both sides by -4.

$\frac{-4x}{-4} = \frac{-2}{-4}$
$x = \frac{1}{2}$

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2 years ago

25/50 as a percentage

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3 years ago

Help me solve for U please help

Maurinko [17]

U + 4/5 = 2 and 1/3

Subtract 4/5 from each side of the equation:

U = (2 and 1/3) - (4/5)

Now it's just problem in plain old adding and subtracting fractions,
just like the ones you've done many times before.

First let's change (2 and 1/3) to a fraction: 2 and 1/3 = 7/3

So you have to find the value of (7/3) - (4/5) .

In order to add or subtract fractions, they need to have a common denominator.
The least common multiple of 3 and 5 is 15, so that's a good choice.

7/3 = 35/15
4/5 = 12/15

Now the problem is: (35/15) - (12/15).

That's 23/15 . . . . . the same thing as <u>1 and 8/15</u> .

That's the value of ' U '. What an ugly number !

8 0

3 years ago

Read 2 more answers

Historically, the proportion of students entering a university who finished in 4 years or less was 63%. To test whether this pro

Neporo4naja [7]

Answer:

z(c) = - 1,64

We reject the null hypothesis

Step-by-step explanation:

We need to solve a proportion test ( one tail-test ) left test

Normal distribution

p₀ = 63 %

proportion size p = 51 %

sample size n = 114

At 5% level of significance α = 0,05, and with this value we find in z- table z score of z(c) = 1,64 ( critical value )

Test of proportion:

H₀ Null Hypothesis p = p₀

Hₐ Alternate Hypothesis p < p₀

We now compute z(s) as:

z(s) = ( p - p₀ ) / √ p₀q₀/n

z(s) =( 0,51 - 0,63) / √0,63*0,37/114

z(s) = - 0,12 / 0,045

z(s) = - 2,66

We compare z(s) and z(c)

z(s) < z(c) - 2,66 < -1,64

Therefore as z(s) < z(c) z(s) is in the rejection zone we reject the null hypothesis

5 0

3 years ago

oee [108]

Answer: (assuming the first three terms are -6, -2, 2)

(a) f(n) = 4n - 10

(b) 30

Step-by-step explanation:

(So, just as a preface, I made this answer assuming the first three terms are -6, -2, and 2 since I couldn't find a provided fourth term as the problem said)

(a) In order to create an equation for an arithmetic sequence, you need to find the common difference(d) and the 0th term. You can find the common difference by finding the difference between two consecutive terms:

2 - (-2) = 4 (or (-2) - (-6) = 4), so d = 4

Now, you need to find the 0th term. To do this, you can just subtract the d from the first term, -6:

-6 - 4 = -10.

At this point, you can write the equation:

f(n) = -10 + 4n (this is the 0th term plus the common difference, 4, times the nth term)

f(n) = 4n - 10 (reorganize by value of exponents)

(b) In order to find the 10th term, you just need to plug it into the previous equation:

where n = 10, and f(n) = 4n - 10,

f(n) = 4(10) - 10 (substitute n into the equation)

f(n) = 40 - 10 (multiply the term in the parenthesis by the constant)

f(n) = 30 (subtract)

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3 years ago