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Ksivusya [100]
2 years ago
8

(x+1)^2+(x-1)^2-2x(x+2)=0

Mathematics
1 answer:
antoniya [11.8K]2 years ago
8 0

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

  • (x+1)^2+(x-1)^2-2x(x+2)=0
  • x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0
  • (x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0
  • -4x + 2 = 0

Step 2: Subtract 2 from both sides.

  • -4x + 2 - 2 = 0 - 2
  • -4x = -2

Step 3: Divide both sides by -4.

  • \frac{-4x}{-4} = \frac{-2}{-4}
  • x = \frac{1}{2}
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Answer:

2

Step-by-step explanation:

Given:

-2(1-4x)=3x+8

Let's distribute the parenthesis

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Let's subtract -3x from both sides

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Let's add 2 to both sides

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Now, let's divide both sides by 5 to get x alone

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Step-by-step explanation:

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Answer:i think its the first one


Step-by-step explanation:

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FALSE

Step-by-step explanation:

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First question
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Second qustion
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