Question

(x+1)^2+(x-1)^2-2x(x+2)=0

Answer 1

Answer:

x = 1/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

• $(x+1)^2+(x-1)^2-2x(x+2)=0$
• $x^2 + 2x + 1 + x^2 - 2x + 1 -2x^2 -4x = 0$
• $(x^2 + x^2-2x^2) + (2x-2x-4x)+(1+1)=0$
• $-4x + 2 = 0$

Step 2: Subtract 2 from both sides.

• $-4x + 2 - 2 = 0 - 2$
• $-4x = -2$

Step 3: Divide both sides by -4.

• $\frac{-4x}{-4} = \frac{-2}{-4}$
• $x = \frac{1}{2}$