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ss7ja [257]
3 years ago
6

When solving the equation 2x + 5 = 13, what is your first step?

Mathematics
1 answer:
Olin [163]3 years ago
8 0

Answer:

A) Subtract 5 from each side

Step-by-step explanation:

This would be your first step, then you would want to isolate your variable so you would divide both sides by 2.

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Answer:

The answer will be y-4=-2(x+1)

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Which property of addition is shown in the equation below?
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Answer:

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Step-by-step explanation:

because ur adding zero

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How many different teams of 11 players can be chosen from a soccer squad of 16
Lerok [7]
1 because 11 can only go into 16 once
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show all work to multiply 3 plus the square root of negative 16 times 6 minus the square root of negative 64
Aloiza [94]

Answer:

\Huge \boxed{3+16i}

\rule[225]{225}{2}

Step-by-step explanation:

3+\sqrt{-16} * 6-\sqrt{-64}

Using imaginary number rule : \sqrt{-n} =\sqrt{n} *i

Where n is a positive integer.

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Multiplying.

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Combining like terms.

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\rule[225]{225}{2}

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4 years ago
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Find the angle between the vectors. (First find an exact expression and then approximate to the nearest degree.)
Luda [366]

Answer:

a.b = (1*0) + (-4*2) +(1*-2)= -10

And replacing we got:

cos \theta = \frac{-10}{\sqrt{18} \sqrt{8}}= -\frac{10}{\sqrt{144}}= -\frac{10}{12}= -\frac{5}{6}

And we can find the angle with the inverse cosine function and we got:

\theta =cos^{-1} (-\frac{5}{6})= 146.44°

Step-by-step explanation:

for this case we can use the following identity:

cos \theta = \frac{a.b}{|a| |b|}

We can begin finding the norm for each vector and we got:

|a| =\sqrt{(1)^2 +(-4)^2 +(1)^2}= \sqrt{18}

|b| =\sqrt{(0)^2 +(2)^2 +(-2)^2}= \sqrt{8}

Now we can find the dot product and we got:

a.b = (1*0) + (-4*2) +(1*-2)= -10

And replacing we got:

cos \theta = \frac{-10}{\sqrt{18} \sqrt{8}}= -\frac{10}{\sqrt{144}}= -\frac{10}{12}= -\frac{5}{6}

And we can find the angle with the inverse cosine function and we got:

\theta =cos^{-1} (-\frac{5}{6})= 146.44°

5 0
3 years ago
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