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skelet666 [1.2K]
3 years ago
12

X² + 7x + 12 factorise it​

Mathematics
1 answer:
Sidana [21]3 years ago
4 0

Step-by-step explanation:

x²+7x+12

x²+4x+3x+12

x(x+4)+3(x+4)

(x+3)(x+4)

hope it helps

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If the nth term of the sequence -1 , 4, 9, 14..... Is 129. Then find the value of n. ​
Leya [2.2K]

Answer:

27

Step-by-step explanation:

129-(-1) = 130

130/5 = 26

26+1 = 27

8 0
3 years ago
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Rearrange b + 4 = a to b=
mojhsa [17]
b+4=a\\
b=a-4
4 0
3 years ago
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Hi please help me no links thank you
olya-2409 [2.1K]

Step-by-step explanation: (I'm not gonna' do it <em>all</em> for you tho)

to convert from <u>percent to fraction</u>:

70% = \frac{70}{100} =\frac{7}{10}

to convert from <u>fraction to percent</u>:

\frac{11}{20}=\frac{55}{100} = 55%

to convert from <u>fraction to decimal</u>:

\frac{3}{25} =\frac{12}{100} =0.12

to convert from <u>decimal to fraction</u>:

1.25=\frac{125}{100} =1\frac{25}{100} =1\frac{1}{4}

to convert from <u>percent to decimal</u>:

0.2% = \frac{0.2}{100} =0.002

to convert from <u>decimal to percent</u>:

0.4= (0.4*100)% = 40%

With that, you can solve the rest on your own

4 0
3 years ago
Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec
expeople1 [14]

Answer:

cot x = \frac{cos x}{sin x}

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

cos x cot x + sin x

We know from math properties that the definition for cot is cot x = \frac{cos x}{sin x}

If we use this definition we got:

cos x \frac{cos x}{sin x} + sin x

\frac{cos^2 x}{sin x} +sin x

Now we can use the following identity:

sin^2 x + cos^2 x =1

Solving for cos^2 x we got cos^2 x =1 -sin^2 x and replacing this we got:

\frac{1-sin^2 x}{sin x} +sin x

\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x

csc x -sin x + sin x = csc x

And then the best option for this case would be:

b.csc x

4 0
4 years ago
Add an intersection the red light times normally distributed by the mean of three minutes and a standard deviation of .25 minute
Soloha48 [4]

95% of red lights last between 2.5 and 3.5 minutes.

<u>Step-by-step explanation:</u>

In this case,

  • The mean M is 3 and
  • The standard deviation SD is given as 0.25

Assume the bell shaped graph of normal distribution,

The center of the graph is mean which is 3 minutes.

We move one space to the right side of mean ⇒ M + SD

⇒ 3+0.25 = 3.25 minutes.

Again we move one more space to the right of mean ⇒ M + 2SD

⇒ 3 + (0.25×2) = 3.5 minutes.

Similarly,

Move one space to the left side of mean ⇒ M - SD

⇒ 3-0.25 = 2.75 minutes.

Again we move one more space to the left of mean ⇒ M - 2SD

⇒ 3 - (0.25×2) =2.5 minutes.

The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.

Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)

Therefore, the percent of  red lights that last between 2.5 and 3.5 minutes is 95%

8 0
4 years ago
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