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scoray [572]
3 years ago
10

3v² - 54v + 240 = 0 Factoring

Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer:

v = 10 , 8

Step-by-step explanation:

You might be interested in
5/8=1/2/x<br> solve for x.
just olya [345]

Answer:

4/5

Step-by-step explanation:

5/8=1/2/x

x=(1/2)/(5/8)

x=(1/2)(8/5)

x=8/10

simplify

x=4/5

7 0
3 years ago
Make x the subject of the formula<br>3(c - bx) = 18​
MrRa [10]

Answer:

x = c - a / -b

Step-by-step explanation:

8 0
3 years ago
Multiply (sqrt 10 + 2 sqrt 8) (sqrt 10 -2 sqrt 8)
sveta [45]

(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8}) = -22

<em><u>Solution:</u></em>

<em><u>Given that we have to multiply the given expression</u></em>

Given is:

(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8})

We have to multiply the above expression

<em><u>Apply the difference of two squares formula</u></em>

(a+b)(a-b) = a^2-b^2

Similarly for,

(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8})

We have,

a = \sqrt{10}\\\\b = 2\sqrt{8}

<em><u>Thus the equation becomes,</u></em>

(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8}) = (\sqrt{10})^2 - (2\sqrt{8})^2\\\\Simplify\\\\(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8}) =(\sqrt{10} \times \sqrt{10}) - (2\sqrt{8} \times 2\sqrt{8})

Use the below rule,

\sqrt{a} \times \sqrt{a} = a

<em><u>Therefore, the above equation becomes,</u></em>

(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8}) =10 - 4 \times 8\\\\(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8}) = 10 - 32\\\\(\sqrt{10} + 2\sqrt{8})(\sqrt{10} - 2\sqrt{8}) =-22

Thus upon multiplying the given expression, solution is -22

8 0
3 years ago
Read 2 more answers
Can someone help me out?
Alexeev081 [22]

Answer: factorise the equation 49x^2+70x+25

Step-by-step explanation:

49x^2+70x+25

(7x)^2+2*7x*5+(5)^2

(7x+5)(7x+5)

therefore the sides of the square are (7x+5)(7x+5)

7 0
3 years ago
a two number digit is chosen at random , what is the probability that the chosen number is a multiple of 7
ExtremeBDS [4]
13/90

so there are 90 two digit numbers.
there are a 13 two digit numbers divisible by 7. so there is a 13/90 probability of a two digit number being selected at random that’s divisible by 7
7 0
3 years ago
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