Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
f = (9c/5) + 32
Step-by-step explanation:
im pretty sure maybe
Answer: -1
Step-by-step explanation: A typical quadratic equation is 
and the maximum value formula is -b/2a, so let plug it in -4/2(-4) which equals 1/2. Then let plug 1/2 into the equation,
-4(1/2)^2+4(1/2)-2=
-1+2-2=
-1
Your answer would be A hope this helps!
3x^2 - 8x + 5
3x^2 - 3x - 5x + 5
3x(x - 1) - 5(x - 1)
(x - 1)(3x - 5)
The answer is: (x - 1)(3x - 5).
