Sorry bro I don’t know the answer but try sharing it again because it is not showing for many people
Answer:So, since it is continuously, we need to think of PERT
A=P\times e^{rt}
So, we just plug our numbers in to solve for T
8000=4000e^{.07t}\\\ln(8000)=\ln(4000e^{.07t})\\\ln(8000) = \ln(4000) + \ln(e^{.07t})\\\ln(8000)=\ln(4000)+.07t\ln(e)\\\ln(8000)=\ln(4000)+.07t\\\frac{\ln(8000)}{\ln(4000)}=.07t\\\frac{\ln(8000)}{.07\ln(4000)}=t\\ 15.479=t
It will take 15.479 years
Step-by-step explanation:
8.5, since there are 2 significant digits, the only 2 numbers would be 8 and 4, so round at 4 since 5 isn't included by is above and equal to 5
25 weeks
178 + (3 x 25)
178 + 75 = 253
203 + (2 x 25)
203 + 50 = 253
Correct answer is 25 weeks.
