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-6 4/9 which means it would be a repeating decimal
Answer:
<h2>x + 2y = 10</h2>
Step-by-step explanation:
The standard form of an equation of a line:
![Ax+By=C](https://tex.z-dn.net/?f=Ax%2BBy%3DC)
The point-slope form of an equation of a line:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
m - slope
(x₁, y₁) - point
We have the point (6, 2) and the slope m = -1/2. Substitute:
![y-2=-\dfrac{1}{2}(x-6)](https://tex.z-dn.net/?f=y-2%3D-%5Cdfrac%7B1%7D%7B2%7D%28x-6%29)
Convert to the standard form:
<em>multiply both sides by 2</em>
![2y-4=-(x-6)](https://tex.z-dn.net/?f=2y-4%3D-%28x-6%29)
<em>add 4 to both sides</em>
<em>add x to both sides</em>
![x+2y=10](https://tex.z-dn.net/?f=x%2B2y%3D10)
Answer:
a^3 + b^3
Step-by-step explanation:
(a + b)(a^2-ab+b^2)
a(a^2 -ab +b^2) +b(a^2-ab+b^2)
a^3 - a^2b +ab^2 + ba^2 -ab^2 +b^3
a^3 -a^2b +a^2b ab^2-ab^2 + b^3
final answer
a^3 + b^3
Slope of AB is different to the slope of BC is the answer.
Answer:
.
Step-by-step explanation:
Given:
In Right Angle Triangle GIH
∠ I = 90°
GI = 7 ....Side opposite to angle H
GH = 10 .... Hypotenuse
To Find:
m∠H = ?
Solution:
In Right Angle Triangle ABC ,Sine Identity,
![sin \ H = \frac{Oppsite\ side\ to\ \angle H}{Hypotenuse}](https://tex.z-dn.net/?f=sin%20%5C%20H%20%3D%20%5Cfrac%7BOppsite%5C%20%20side%5C%20%20to%5C%20%20%5Cangle%20H%7D%7BHypotenuse%7D)
Substituting the values we get;
![sin\ H = \frac{7}{10} = 0.7](https://tex.z-dn.net/?f=sin%5C%20H%20%3D%20%5Cfrac%7B7%7D%7B10%7D%20%3D%200.7)
Now taking
we get;
![\angle H = sin^{-1}\ 0.7 = 44.427](https://tex.z-dn.net/?f=%5Cangle%20H%20%3D%20sin%5E%7B-1%7D%5C%200.7%20%3D%2044.427)
rounding to nearest tenth we get.
.
Hence
.