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Anna [14]
3 years ago
15

The vertices of a swimming pool are E(5, 5), F(5, 20), G(35, 20), and H(35, 5). The endpoints of a line that divides the pool in

to two sections are J(15, 5) and K(15, 20). The coordinates are measured in meters. What is the area of each section?
Mathematics
1 answer:
sleet_krkn [62]3 years ago
3 0

Answer:

Step-by-step explanation:

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Solve the equation <br>y=2x-4, 3x+y=11​
Ostrovityanka [42]

Answer:

(3, 2)

Step-by-step explanation:

Given the 2 equations

y = 2x - 4 → (1)

3x + y = 11 → (2)

Substitute y = 2x - 4 into (2)

3x + 2x - 4 = 11

5x - 4 = 11 ( add 4 to both sides )

5x = 15 ( divide both sides by 5 )

x = 3

Substitute x = 3 into (1) for corresponding value of y

y = (2 × 3) - 4 = 6 - 4 = 2

Solution is (3, 2)

5 0
3 years ago
Read 2 more answers
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
What is 788 divided by 14 in a long division model?
Fiesta28 [93]
Here's how you do long division

6 0
3 years ago
PLEASE HELP!!
aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

1/3 * 6 = 2

Step 2.

an = 1/3 * 6 ^3-1

an = 1/3 * 6 ^2

1/3 * 36 = 12

Hope this helps.

4 0
3 years ago
Suppose that the population of deer in a state is 1,500 and is growing 2% each year. Predict the population after 4 years.
DIA [1.3K]
Yes that's right. B 1,624
5 0
3 years ago
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