<h2>cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenuse </h2>

cos 36= x/8√5+1/4 = x/8

4.7 is the approximate answer

8 0

3 years ago

The midpoint of AB is M(1, -4). If the coordinates of A are (-3,-6), what are the coordinates of B?

kramer

Answer:

The coordinates of B is (5,-2)

Step-by-step explanation:

In order to find the coordinates of B, you have to use midpoint formula. Then substitute the following values into the formula :

$m = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )$

Let (x1,y1) be A (-3,-6),

Let (x2,y2) be B,

Let midpoint be M (1,-4),

$(1, - 4) = (\frac{ - 3 + x2}{2} , \frac{ - 6 + y2}{2} )$

$by \: comparison, \:$

$\frac{ - 3 + x2}{2} = 1$

$- 3 + x2 = 2$

$x2 = 5$

$\frac{ - 6 + y2}{2} = - 4$

$- 6 + y2 = - 8$

$y2 = - 2$

6 0

3 years ago

Using a minimum of two sentences, describe how to write the function, f(x) = (x + 2)^2 - 3, in standard form.

Lostsunrise [7]

First, simplify the (x+2)(x+2) with FOIL:
f(x)=( $x^{2} +2x+2x+4$ )-3
Combine like terms
f(x)= $x^{2} +4x+1$
Then you have standard form.

Hope that helps.

3 0

3 years ago

I need help with this question

nydimaria [60]

I cant help i just needa answer something before i cant ask anything else

6 0

3 years ago