3 years ago

Determine the sum of: −10y2+(−3y2)−4y2−(−6y2) the 2 are squared

1 answer:

4 0

-10y^2 + (-3y^2) - 4y^2 - (-6y^2) =
-10y^2 - 3y^2 - 4y^2 + 6y^2 =
-17y^2 + 6y^2 =
- 11y^2

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