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3 years ago

What is the interior angle of a regular 25 gon

Mathematics

2 answers:

OLga [1]3 years ago

7 0

Answer:

schläfli symbol {50}, t{25}

Coxeter diagram

Symmetry group Dihedral (D50), order 2×50

Internal angle (degrees) 172.8°

5 more rows

Step-by-step explanation:

kaheart [24]3 years ago

4 0

Answer:

Step-by-step explanation:

exterior angle of 25gon = 360/25 = 14.4°

Interior angle = 180 - 14.4 = 165.6°

Interior angle and exterior angles are linear pair

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Solve for n (look at attachment)

Virty [35]

First distribute 6 into the parenthesis so that would be (6n - 18) - 2n = 10. Then erase the parenthesis to make the subtraction easier. So that would be 6n-18-2n=10. Then solve the subtraction by separating the unknown numbers with n and the normal numbers. So 6n-2n=4n 4n-18=10. To find n, add 18 and 10 to make both sides of the equation equal. So that would make 4n=28. Therefore n would be 7 because 28 divided by 4 makes 7.

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3 years ago

Find the slope of (3,43) and (8,113)

Alexandra [31]

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3 years ago

Sin(x)^4+ cos(x)^4=1/2

posledela

I'll assume that what was meant was $\sin ^4 x + \cos ^4 x = \dfrac{1}{2}$ .

The exponent in the funny place is just an abbreviation: $\sin ^4 x = (\sin x)^4$ .

I hope that's what you meant. Let me know if I'm wrong.

Let's start from the old saw

$\cos^2 x + \sin ^2x = 1$

Squaring both sides,

$(\cos^2 x + \sin ^2x)^2 = 1^2$

$\cos^4 x + 2 \cos ^2 x \sin ^2x +\sin ^4x = 1$

$\cos^4 x + \sin ^4x = 1 - 2 \cos ^2 x \sin ^2x$

So now the original question

$\sin ^4 x + \cos ^4 x = \dfrac{1}{2}$

becomes
$1 - 2 \cos ^2 x \sin ^2x = \dfrac{1}{2}$

$4 \cos ^2 x \sin ^2x = 1$

Now we use the sine double angle formula

$\sin 2x = 2 \sin x \cos x$

We square it to see

$\sin^2 2x = 4\sin^2 x \cos^2 x = 1$

Taking the square root,

$\sin 2x = \pm 1$

Not sure how you want it; we'll do it in degrees.

When we know the sine of an angle, there's usually two angles on the unit circle that have that sine. They're supplementary angles which add to $180^\circ$ . But when the sine is 1 or -1 like it is here, we're looking at $90^\circ$ and $-90^\circ$ , which are essentially their own supplements, slightly less messy.

That means we have two equations:

$\sin 2x = 1 = \sin 90^\circ$

$2x = 90^\circ + 360^\circ k \quad$ integer $k$

$x = 45^\circ + 180^\circ k$

or

$\sin 2x = -1 = \sin -90^\circ$

$2x = -90^\circ+ 360^\circ k$

$x = - 45^\circ + 180^\circ k$

We can combine those for a final answer,

$x = \pm 45^\circ + 180^\circ k \quad$ integer $k$

Check. Let's just check one, how about

$x=-45^\circ + 180^\circ = 135^\circ$

$\sin(135)= 1/\sqrt{2}$

$\sin ^4(135)=(1/\sqrt{2})^4 = 1/4$

$\cos ^4(135)=(-1/\sqrt{2})^4 = 1/4$

$\sin ^4(135^\circ) +\cos ^4(135^\circ) = 1/2 \quad\checkmark$

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3 years ago

I need help with number 14

strojnjashka [21]

The ionic compound produced would be Aluminum Oxide or Al2O3.

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3 years ago

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DedPeter [7]

answer-pues hay un cambio de temperatura entonces

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