a telephone pole casts a 10 food shadow. A horse that stands 5.5 feet tall casts a 2.5 foot shadow. How tall is the pole?

Verify the identity. cosine of x divided by quantity one plus sine of x plus quantity one plus sine of x divided by cosine of x

DanielleElmas [232]

Cos(x)/(1+sin(x) + (1+sin(x))/cos(x)=

cos²(x)/cos(x)(1+sin(x)) + (1+sin(x))²/cos(x)(1+sin(x))=

cos²(x)+1+2sin(x)+sin²(x) /cos(x)(1+sin(x))=

2+2sin(x) / cos(x)(1+sin(x))=

2(1+sin(x)) / cos(x)(1+sin(x))=

2/cos(x)=

2*sec(x)

3 0

3 years ago

I have a Brainliest please help

Firdavs [7]

31) ($6 * 2) + $6.25 + $4.25 + $20 = $42.50

32) $50 - $8.25 - $4.25 -$4.25 - $20 = $13.25

33) 6 * 15.99 = 95.94 | $100 - $95.94 = $4.06

34) $10.50 * 8 = 84 | $100 - $84 = $16

Hope this helps! ^^

5 0

3 years ago

There were 2430 Major League Baseball games played in 2009, and the home team won the game in 53% of the games. If we consider t

Ivahew [28]

Answer:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958$

$p_v =P(Z>2.958)=0.0015$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion is significantly higher than 0.5 .

Step-by-step explanation:

1) Data given and notation

n=2430 represent the random sample taken

$\hat p=0.53$ estimated proportion when the home team won the game

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.5 or 50%:

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.958)=0.0015$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion is significantly higher than 0.5 .

8 0

3 years ago

Solve 34x−5<8. Round your answer to the nearest thousandth

Snowcat [4.5K]

Answer:

x < 0.382

Step-by-step explanation:

because we know that 34x is smaller than 13. therefore after division we can find out that x must be smaller than 0.382

3 0

2 years ago

WILL MARK BRAINLIST!! SOS MATH. Look at picture

Aleks [24]

Answer:

Yes, the transformation is a 270° clockwise rotation

Step-by-step explanation:

(-3, 4) ,( -4, 7) and (-2,7) transformed to (-4, - 3), (-7, -4) and (-7, -2).

Rule for 270° clockwise rotation:

(x, y) --> (- y, x)

A transformation that doesn't change the size or shape of an object.

So answer is:

Yes, the transformation is a 270° clockwise rotation

5 0

3 years ago