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4 years ago

Can anyone make a word problem for 2(4+n)

Mathematics

2 answers:

ELEN [110]4 years ago

4 0

Answer:

Zach has n apples his friend gives him 4 more apples(4+n) then his mom doubles the amount of apples he has and give it to Zach 2(4+n). How many apples does zach have now

Anton [14]4 years ago

3 0

Answer:

The sum of four and a number multiplied by two

Step-by-step explanation:

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YALL NEVER ANSWER AH POOP plz help

lakkis [162]

Answer:

The given point A (6,13) lies on the equation. True

The given point B(21,33) lies on the equation. True

The given point C (99, 137) lies on the equation. True

Step-by-step explanation:

Here, the given equation is : $y =\frac{4}{3} x + 5$

Now,check the given equation for the given points.

1) A (6,13)

Substitute x = 6 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (6) + 5 = 4(2) + 5 = 8 + 5 = 13$

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2) B (21,33)

Substitute x = 21 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (21) + 5 = 4(7) + 5 = 28 + 5 = 33$

⇒ y = 33

Hence, the given point B(21,33) lies on the equation.

3) C (99, 137)

Substitute x = 99 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (99) + 5 = 4(33) + 5 = 132 + 5 = 137$

⇒ y = 137

Hence, the given point C (99, 137) lies on the equation.

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3 years ago

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3 years ago

During a big race, Jeff races his car at a rate of 125 miles per hour for 3.2 hours. What is the distance of the race?

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2 years ago

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Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$